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anonymous
 one year ago
A box has 60 balls, of which 22 are red, 19 are blue, and 19 are yellow, as before. Balls are extracted at random but this time not returned to the box. What is the probability that after performing this test three times exactly two are blue and one is red?
anonymous
 one year ago
A box has 60 balls, of which 22 are red, 19 are blue, and 19 are yellow, as before. Balls are extracted at random but this time not returned to the box. What is the probability that after performing this test three times exactly two are blue and one is red?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when i do the calculation i got the answer 1818/17110 but the book answer have 5643/17110, i think i did something wrong my calculation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this what i did to get the calculation \[\frac{ \left(\begin{matrix}19 \\ 2\end{matrix}\right)* \left(\begin{matrix}22 \\ 1\end{matrix}\right)*\left(\begin{matrix}19 \\ 0\end{matrix}\right)}{ \left(\begin{matrix}60 \\ 3\end{matrix}\right)}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3what is the test being performed?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3What is the probability that after performing ***this test*** three times exactly two are blue and one is red? the questions feels like its missing information ... prolly from a different question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k A box has 50 balls, of which 16 are red, 19 are blue, and 15 are yellow. Balls are extracted at random then returned to the box. What is the probability that after performing this test three times exactly two are yellow and one is blue?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0similar but a bit different w/ a number

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3experiment ... might be a better word

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3A box has 60 balls, of which 22 are red, 19 are blue, and 19 are yellow, as before. Balls are extracted at random but this time not returned to the box. What is the probability that after performing this (process) three times exactly two are blue and one is red? rbb brb bbr 3*(22.19.18)/(60.59.58) maybe?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0doing that the number will be large

amistre64
 one year ago
Best ResponseYou've already chosen the best response.31881/17110 is what that turns out to be

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3P(bbr) or P(brb) or P(rbb) are the only ways we can pull 2bs and 1r in 3 pulls right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3and after we pull them out the remaining amounts decrease by 1 22 for red, 19 and 18 for blues and the ball count reduces 60,59,58 for the product of the denominator ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is like this dw:1444575916412:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3not factorial, 3 * (22 P 1) * (19 P 2)  (60 P 3)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3but my solution is even less than yours, so i might not have a grasp of the information

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i wonder what is p1 and p2 p3 use for ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3nPk is the permuations of n objects, k times it is used when the order matters abc not equal bac nCk is the combinations of n objects, k times it is used when the order doesnt matter abc = bac k! nCk = nPk

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we are using the permutation instead of combination

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3yes, or at least as a basis for a model

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3there are 3 ways to pull bbr and each pull has a probability of (22*19*18)/(60*50*58)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3this is assuming it means that we are pulling 3 balls starting at the first pull.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.359, not 50 ... my fingers hate me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k i see the answer dw:1444576774278:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.31881 is what i get for a numerator 5643 is what your book gives, which is 3 times bigger than my outcome. 3*3*(...) where are they coming up with 9 different ways to order it?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3what does "this test" refer to?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have 3*(7524/205320)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as you said the experiment

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3that was my assumption, but my outcome differs from the books outcome. someones got to be wrong, and I assume its me :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3are you looking at the correct solution?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just said about the multistep process

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3even your approach gets the same results as me

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.0I get the same answer as you guys. I am suspicious of the book's answer.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3could it be possible that we are drawing more than 3 of them out for our sample space?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here the answer but do not show the step

amistre64
 one year ago
Best ResponseYou've already chosen the best response.33*(15*15*19)/(60*60*60) = 513/5000 so its the same approach

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3the book solution is wrong then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much for the correcting the confusion

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3im trying to see how they could have gotten an answer 3 times bigger, but other than a simpler human error in inputing it to begin with i cant duplicate it.
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