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anonymous

  • one year ago

What is maximum value of f(x,y)=3x+3y. Using the following inequalities. X>=0. Y>=0. 3x+2y<=18 6x+7y<=42

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  1. anonymous
    • one year ago
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    draw lines 3x+2y=18 and 6x+7y=42 \[x \ge0, y \ge0~ gives~ graph~ lies~infirst~quadrant.\]

  2. anonymous
    • one year ago
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    We have graphed the equation. And worked it out with the answer 18. That's not the right answer.

  3. anonymous
    • one year ago
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    3x+2y=18 x=0,y=9,y=0, x=6 6x+7y=42 x=0,y=6,y=0,x=7 |dw:1444579686748:dw|

  4. anonymous
    • one year ago
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    i think at E,f=3*14/3+3*2=14+6=20 but you need to show at all four points.

  5. anonymous
    • one year ago
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    Yes finally! Thank you so much.

  6. anonymous
    • one year ago
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    yw

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