3a is incorrect
which makes 3b and 3c also incorrect
Ok, let me review it a moment...
sure, i was about to say, try to find the error on your own
and the same mistake is done in 4. you correct one, you correct all!! :)
Hmmm, I don't see what's wrong there. Can you explain?
length = 2t its cube = \( (2t)^3 = 8t^3 \)
basically you forgot the brackets :P
Oh, okay. I'll try doing those again then :)
sure, all 3 a,b,c and 4 a,b,c needs that correction. let me know when you're done, i'll review it again.
lets come to 3b now. \((2t)^3 + 12^3 = (2t+12)((2t)^2 - (2t)\times 12) +12^2 \) makes sense?
i missed the last bracket \((2t)^3 + 12^3 = (2t+12)((2t)^2 - (2t)\times 12 +12^2)\)
got that^^ ?
OK, I get it.
so your answer for 3b should be \((2t+12)(4t^2 -24t +144)\)
now for 3c, its (2t)^3 not (8t)^3 ... so (2*7)^3 + 12^3 = 14^3 +12^3 = .........
same thing goes for 4b and 4c :)
\((2t+12)(4t^2 -24t +144)\) ^^ that can be further factorized \(8(t + 6)(t^2 - 6t + 36)\)
typing error in 4b
everything else is correct :)
I've corrected that typo:) Thanks for helping me:)