quickstudent
  • quickstudent
Can someone please check this for me? Factoring Sum of Cubes
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
hartnn
  • hartnn
3a is incorrect
hartnn
  • hartnn
which makes 3b and 3c also incorrect

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

quickstudent
  • quickstudent
Ok, let me review it a moment...
hartnn
  • hartnn
sure, i was about to say, try to find the error on your own
hartnn
  • hartnn
and the same mistake is done in 4. you correct one, you correct all!! :)
quickstudent
  • quickstudent
Hmmm, I don't see what's wrong there. Can you explain?
hartnn
  • hartnn
length = 2t its cube = \( (2t)^3 = 8t^3 \)
hartnn
  • hartnn
basically you forgot the brackets :P
quickstudent
  • quickstudent
Oh, okay. I'll try doing those again then :)
hartnn
  • hartnn
sure, all 3 a,b,c and 4 a,b,c needs that correction. let me know when you're done, i'll review it again.
quickstudent
  • quickstudent
Here it is now, corrected :) @hartnn
hartnn
  • hartnn
lets come to 3b now. \((2t)^3 + 12^3 = (2t+12)((2t)^2 - (2t)\times 12) +12^2 \) makes sense?
hartnn
  • hartnn
i missed the last bracket \((2t)^3 + 12^3 = (2t+12)((2t)^2 - (2t)\times 12 +12^2)\)
hartnn
  • hartnn
got that^^ ?
quickstudent
  • quickstudent
OK, I get it.
hartnn
  • hartnn
so your answer for 3b should be \((2t+12)(4t^2 -24t +144)\)
hartnn
  • hartnn
now for 3c, its (2t)^3 not (8t)^3 ... so (2*7)^3 + 12^3 = 14^3 +12^3 = .........
hartnn
  • hartnn
same thing goes for 4b and 4c :)
hartnn
  • hartnn
\((2t+12)(4t^2 -24t +144)\) ^^ that can be further factorized \(8(t + 6)(t^2 - 6t + 36)\)
quickstudent
  • quickstudent
OK, now I've correct 3 and 4 again.
hartnn
  • hartnn
typing error in 4b
hartnn
  • hartnn
everything else is correct :)
quickstudent
  • quickstudent
I've corrected that typo:) Thanks for helping me:)
hartnn
  • hartnn
welcome ^_^

Looking for something else?

Not the answer you are looking for? Search for more explanations.