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korosh23

  • one year ago

Pre-calculus 12 Question! Please wait for the attachment

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  1. korosh23
    • one year ago
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  2. alivejeremy
    • one year ago
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    its b

  3. korosh23
    • one year ago
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    I don't want answer. I want explanation.

  4. alivejeremy
    • one year ago
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    oh ok

  5. alivejeremy
    • one year ago
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    u want me to teach u

  6. korosh23
    • one year ago
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    Yes please

  7. alivejeremy
    • one year ago
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    ok

  8. alivejeremy
    • one year ago
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    ok

  9. korosh23
    • one year ago
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    So?

  10. amistre64
    • one year ago
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    there are 2 different questions there ... those arent options so, what is your definition of a radical? is that the sqrt function or something more general?

  11. korosh23
    • one year ago
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    It is the square root function. |dw:1444575818648:dw|

  12. korosh23
    • one year ago
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    |dw:1444575834121:dw|

  13. amistre64
    • one year ago
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    your end point is the 'vertex' it is how we define the translation of it

  14. korosh23
    • one year ago
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    ok

  15. amistre64
    • one year ago
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    if we subtract the end point from the points given we can normalize it to the origin

  16. korosh23
    • one year ago
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    ok, actually I did part a to point. I just do not understand something. Can I ask you? It saves a lot of time

  17. amistre64
    • one year ago
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    2,5 6,1 -2-5 -2-5 ----------- 0,0 4,-4 might be simpler to visualize

  18. amistre64
    • one year ago
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    sure

  19. korosh23
    • one year ago
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    |dw:1444575990367:dw|

  20. korosh23
    • one year ago
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    Assuming that the vertex is (0,0) like what you mentioned. We can see that we have a vertical translation of 5 uunits up , so k=5 horizontal translation of 2 units right h=2 reflection in x-axis, so a is -. However, I do not know how to find the value of a

  21. amistre64
    • one year ago
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    |dw:1444583364743:dw|

  22. amistre64
    • one year ago
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    since we have normalized it to the origin, h and k = 0

  23. amistre64
    • one year ago
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    a sqrt(x) = -4, when x=4 a sqrt(4) = -4 2a = -4 etc ...

  24. korosh23
    • one year ago
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    Could you please tell me how did you get the point (4,-4)?

  25. amistre64
    • one year ago
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    again, i subtracted the vertex (the end point) from the stated points so that the end point is at 0,0 do you agree that (2,5) - (2,5) = (0,0) ?

  26. korosh23
    • one year ago
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    yes

  27. amistre64
    • one year ago
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    not sure how you study this, some people do a translation T(x-2,y-5)

  28. amistre64
    • one year ago
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    so we have to pass thru the point (6,1), translated to (6-2,1-5)

  29. korosh23
    • one year ago
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    right! that is awsome :)

  30. korosh23
    • one year ago
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    that is the answer.

  31. amistre64
    • one year ago
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    i would hope so lol

  32. korosh23
    • one year ago
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    @amistre64 thank you for your help my friend. :)

  33. amistre64
    • one year ago
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    youre welcome, and good luck ;)

  34. korosh23
    • one year ago
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    thanks

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