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amy0799
 one year ago
d/dx m(x) where m(x) is the tangent line to curve x^2+xyy^2 = 1 at point (2,3)
amy0799
 one year ago
d/dx m(x) where m(x) is the tangent line to curve x^2+xyy^2 = 1 at point (2,3)

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the slope of a line is its derivative ...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2d/dx (tangent line to a curve) = y', or slope of the curve

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0yes, so I just need to take the derivative of x^2+xyy^2 = 1?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0i asked my other friends, and they took the 2nd derivative. so I'm now confused...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2\[y_{tan}=f'(a)(xa)+f(b)\] \[\frac d{dx}y_{tan}=f'(a)\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the derivative of a line, is its slope

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444585385770:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2regardless of the curve ... the function we are taking the derivative of is a line

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0\[m'(x)=\frac{ 2xy }{ x2y }\] is this correct?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2maybe .. now you gonna make me work lol x^2+xyy^2 = 1 2xx'+x'y+xy' 2yy' = 0 2 3 2 3 4+3+2y' 6y' = 0 (26)y' = 7

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2i tend to have less error when i plug in and then solve for y'
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