anonymous
  • anonymous
Piece wise - defined form of function N(x) = 20 - |x-5| N(x) = ( ax + b x >= 5 cx + d x< 5 find a,b,c,d So far i've come up with 1x -5 >= 5 1x+5 < 5 But its not making sense and Im stuck. Any thoughts?
Mathematics
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anonymous
  • anonymous
Piece wise - defined form of function N(x) = 20 - |x-5| N(x) = ( ax + b x >= 5 cx + d x< 5 find a,b,c,d So far i've come up with 1x -5 >= 5 1x+5 < 5 But its not making sense and Im stuck. Any thoughts?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
is 20-lx-5l equal to anything?
anonymous
  • anonymous
Its an absolute value function, N(x) = 20 - |x-5|
anonymous
  • anonymous
sorry I can't help you :(

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anonymous
  • anonymous
Ok thanks for looking
amistre64
  • amistre64
define the function in 2 pieces, split at the point of the vertex
amistre64
  • amistre64
|dw:1444588814239:dw|
anonymous
  • anonymous
Oh, ok. This puts me in the right direction
anonymous
  • anonymous
thanks
amistre64
  • amistre64
by splitting the function at the vertex, we are piecing together the absolute value portion let (x-5) be positive 20 - (x-5) ------------------ let (x-5) be negative 20 - -(x-5) to define which side is which ... let x=0 to see which piece matches the original setup
amistre64
  • amistre64
20-x+5 20+x-5 when x=0; 20 - |-5| = 15; and since 0<5 this piece conforms to when x<5

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