A student adds 15.0 mL 2.00 M Acetic Acid and 10.0 mL 0.03 M HCl. Determine the pH of the resulting solution.
Ka HC2H3O2 = 1.80E-5
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
@aaronq @TIMO86M @mathmale
the contribution of [H+] by the acetic acid alone is very considering the small dissociation of a weak acid.
Anyway you can calculate the [H+] by the weak acid and calculate how many moles of H+ you have in the 15 mL (~ 0.00009 moles H+)
Also you can calculate how many moles of H+ you have in the 10mL of 0.03M HCl acid. (~0.0003 mol).
The amount of H+ given by the strong acid is higher than the weak acid and increasing the amount of H+ the weak acid is going to dissociate less than being alone and the amount of H+ given to the mix by the weak acid is going to be even less than 0.00009 moles. Besides the volume is change and the concentration of the weak acid will decrease
You can calculate the pH with the value of the concentration of the strong acid considering the dilution in the change of volume.
Calculate the new concentration of the 10 mL 0.03M HCl in 25mL final volume, and calculate the pH with that concentration.
I got pH 1.92
How can you use hasselbalchs equation when there's 2 acids @Cuanchi