Finding Percents
I have examples of this in my book, but i cant quite seem how to do this. ;-; I need help on questions like "# is what percent of #?"
if you could inform me on the steps that would be great :3

- anonymous

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- katieb

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- pooja195

See if this helps its just an example
|dw:1444588270448:dw|

- anonymous

? kinda confused ;-;

- anonymous

so 25/100 im guessing :l

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## More answers

- anonymous

do you understand how it is set up, though?

- pooja195

Is there a specific question that you have that you need help on ?

- anonymous

i know your supposed to take the first number and put it as numerator and take second number as denominator, reduce, and change to decimal... but confused on how to go about that. and no i dont have a specific question i just want to know how to do it so i can do it on my own.

- pooja195

Try this
24 is what percent of 32?

- phi

you can translate
A is what percent of B?"
to
A= x% * B
(the is means equals, the % of B means multiply times B)

- anonymous

okay, with this set up, ignore the decimal for now. if you set it up as is over of, you cross-multiply the "fractions", then divide to isolate x to find the value of the missing number

- anonymous

i think it would be
24/32 then reduced to 12/16 then 6/8 and then 3/4...

- anonymous

going with pooja's problem :l

- pooja195

No thats incorrect... we need to make it a fraction or division problem
all we need to do is 24/32 and you would divide it

- anonymous

so .75?
and im guessing it would be 75% as the answer?

- anonymous

24/32 = x/100

- anonymous

75/100?

- anonymous

;-;

- anonymous

kody, you're making it more complex than it needs to be

- anonymous

/).- k...

- anonymous

how does i makes it less complex then? ;-;

- anonymous

this is just what im going from out of the book.

- anonymous

24/32 = x/100 is the values plugged into the formula. this is how the problem is set up

- anonymous

is this part clear?

- anonymous

yeah i guess :l

- anonymous

you then multiply the first numerator (top) by the second denominator (bottom). and the same with the first denominator and second numerator

- anonymous

sooo 24*32?

- anonymous

no. that would be the first numerator and the first denominator

- anonymous

OH OH OK i sees now

- anonymous

so i multiply diagonally? ;l so 24*100...???

- anonymous

yes :)

- anonymous

and 32 by x

- anonymous

but whats the x? /).-

- anonymous

patience, young grasshopper. the lesson is not yet finished :P

- anonymous

the x would be the 2400?

- anonymous

the equation should now look like (because you multiplied x by 32) 32x = 2400 (from multiplying 24 by 100). then, you need to isolate the x. you do this by dividing both sides by 32

- anonymous

/)o_o(\ big words

- anonymous

ummmm

- anonymous

equation is a math problem with an equal sign. isolate means to make alone

- anonymous

k.

- anonymous

so i divide 2400 by 32?

- anonymous

yes

- anonymous

ohkai

- anonymous

75 ;-;

- anonymous

oh so its 75% YAI IM DONE RITE?

- anonymous

the answer, 75% was never wrong. just how you were trying to find it

- anonymous

/).-

- skullpatrol

All percent problems come down to solving this equation:
$$\Huge\frac{x}{100}=\frac{a}{b}$$

- anonymous

the method you were trying only works on a perfect fraction. something that divides together. what if i'd asked 22 is what percent of 23?

- anonymous

ohohohohoho ok :3 ty vry much

- anonymous

i think i gots it now

- anonymous

okay, lets try another one just to make sure. okay?

- skullpatrol

|dw:1444590124420:dw|

- anonymous

kody, what is 26% of 60?

- anonymous

oh sorry i had to brb. im back now

- anonymous

do you think you can find this?

- anonymous

yeah

- anonymous

i know how to do that ;-;

- anonymous

i hope.

- anonymous

this one DOES work with the decimals

- anonymous

15.60?

- anonymous

yes. one more

- anonymous

kK

- anonymous

42 is 60 percent of what?

- anonymous

70

- anonymous

i tink

- anonymous

correct :)

- anonymous

YAIIIII! :3 Ty So Muccch ! ;3

- anonymous

congrats on learning to find percents :)

- anonymous

^_^
/)(\

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