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## anonymous one year ago What is the slope of the line passing through the points (1, –5) and (4, 1)? A. 2 B. - 4/5 C. 5/4 D. -2 I think C

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1. pooja195

$\LARGE \frac{y_2-y_1}{x_2-x_1}=slope$

2. AlexandervonHumboldt2

use slope formula $\frac{ y_1-y_2 }{ x_1-x_2 }$

3. AlexandervonHumboldt2

substitute your values and solve

4. AlexandervonHumboldt2

(x,y) (-5-1)/(1-4)=solve

5. pooja195

$\LARGE \frac{1-(-5)}{4-1}=slope$

6. anonymous

-2 ?

7. AlexandervonHumboldt2

(-6)/(-3)=6/3=???

8. AlexandervonHumboldt2

no not -2.

9. pooja195

@AlexandervonHumboldt2 chill let the asker reply

10. AlexandervonHumboldt2

what do you mean?

11. anonymous

ooo so it would just be 2 ? , I understand what I did wrong

12. AlexandervonHumboldt2

yeah

13. anonymous

Okay Ty

14. AlexandervonHumboldt2

@pooja195 please don't make useless remarks to me. I'm 21 and I know what to do better than you. you know rules of os not better than me.

15. pooja195

@AlexandervonHumboldt2 age is just a number. I asked you to be patient because the asker was still trying to reply and you were trying to rush things we help people out for them to understand not rush through so that they remain confused. I apologize if you though my comment was a useless remark.

16. AlexandervonHumboldt2

you your self didn't waited for her reply and posted a new comment

17. AlexandervonHumboldt2

if you are A it doesn't mean you can command me. i was patient. everyone has different point of views. i will write a complain on you if you will ever tell me such things. mods didn't remarked me, so I'm patient.

18. pooja195

Go ahead write a complain on me i dont really care i'm resigning as ambi anways

19. AlexandervonHumboldt2

Mods didn't told me that i'm not patient. Thus I'm patient and askers also didn't complained that i'm not patient. You are still trying to show that i'm a baby and you are supervisor for me.

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