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Lena772
 one year ago
A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution.
Ka HC2H3O2 = 1.80E5
Lena772
 one year ago
A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution. Ka HC2H3O2 = 1.80E5

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Lena772
 one year ago
Best ResponseYou've already chosen the best response.0@Cuanchi I've tried the same method with this and got it wrong twice.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is sodium acetate it is a salt and the HCl acid you may have a buffer here. Acetic/Acetate

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0does that mean i can use hasselbach?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0What was the method you used before?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you do the titration of the Acetate with the HCl and calculate how much acetate and Acetic you have. Yes you can use Hasselbach

Lena772
 one year ago
Best ResponseYou've already chosen the best response.04.7447274949+log(1.2/0.8) =4.92 Is this right?

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0I used the hasselbach method but i may have plugged in something wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let me think doesnt looks that easy how i was thinking in the biguining

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0I submitted and that was right. I must have been plugging stuff in wrong. Thanks for all your help :)
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