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Lena772

  • one year ago

A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution. Ka HC2H3O2 = 1.80E-5

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  1. Lena772
    • one year ago
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    @Cuanchi I've tried the same method with this and got it wrong twice.

  2. cuanchi
    • one year ago
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    this is sodium acetate it is a salt and the HCl acid you may have a buffer here. Acetic/Acetate

  3. Lena772
    • one year ago
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    does that mean i can use hasselbach?

  4. Photon336
    • one year ago
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    What was the method you used before?

  5. cuanchi
    • one year ago
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    you do the titration of the Acetate with the HCl and calculate how much acetate and Acetic you have. Yes you can use Hasselbach

  6. Lena772
    • one year ago
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    4.7447274949+log(1.2/0.8) =4.92 Is this right?

  7. Lena772
    • one year ago
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    I used the hasselbach method but i may have plugged in something wrong

  8. cuanchi
    • one year ago
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    let me think doesnt looks that easy how i was thinking in the biguining

  9. Lena772
    • one year ago
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    I submitted and that was right. I must have been plugging stuff in wrong. Thanks for all your help :)

  10. cuanchi
    • one year ago
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    ok you are lucky!!

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