A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution. Ka HC2H3O2 = 1.80E-5

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A student adds 15.0 mL 2.00 M sodium acetate and 10.0 mL 2.0 M HCl. Determine the pH of the resulting solution. Ka HC2H3O2 = 1.80E-5

Chemistry
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@Cuanchi I've tried the same method with this and got it wrong twice.
this is sodium acetate it is a salt and the HCl acid you may have a buffer here. Acetic/Acetate
does that mean i can use hasselbach?

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Other answers:

What was the method you used before?
you do the titration of the Acetate with the HCl and calculate how much acetate and Acetic you have. Yes you can use Hasselbach
4.7447274949+log(1.2/0.8) =4.92 Is this right?
I used the hasselbach method but i may have plugged in something wrong
let me think doesnt looks that easy how i was thinking in the biguining
I submitted and that was right. I must have been plugging stuff in wrong. Thanks for all your help :)
ok you are lucky!!

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