anonymous
  • anonymous
PLEASE HELP I REALLY NEED TO PASS! Find The Product. (t-sa)(9t+6sa)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Mehek14
  • Mehek14
use FOIL
calculusxy
  • calculusxy
|dw:1444596888643:dw|
calculusxy
  • calculusxy
I am not sure if this is correct ...

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calculusxy
  • calculusxy
sorry. one moment
Mehek14
  • Mehek14
\(\tt{(t-sa)(9t+6sa)\\t*9t=9t^2\\-sa*9t=-9tsa\\t*6sa=6tsa\\-sa*6sa=-6sa^2\\9t^2-9tsa+6tsa-6sa^2}\)
Mehek14
  • Mehek14
you have to combine like terms
Mehek14
  • Mehek14
\(\tt{-9tsa+6tsa=-3tsa}\)
calculusxy
  • calculusxy
yes that's correct
freckles
  • freckles
|dw:1444597193897:dw|
calculusxy
  • calculusxy
@Mehek14 How did you change the font? I only know /rm and /scr
freckles
  • freckles
-sa*6sa=-6s^2a^2
Mehek14
  • Mehek14
i used \tt
freckles
  • freckles
|dw:1444597235822:dw|
calculusxy
  • calculusxy
@freckles YEAH!
Mehek14
  • Mehek14
\(\tt{9t^2-3tsa-6s^2a^2}\)
anonymous
  • anonymous
So 9t^2-3tsa-6sa?
calculusxy
  • calculusxy
no use @Mehek14 's one.
anonymous
  • anonymous
Thanks Guys your real life savers
anonymous
  • anonymous
(4a-ts)(2a+2ts)? Its so confusing
anonymous
  • anonymous
@Mehek14
Mehek14
  • Mehek14
\(\tt{(4a-ts)(2a+2ts)\\4a*2a=8a^2\\4a*2ts=8ats\\-ts*2a=-2ats\\-ts*2ts=-2t^2s^2}\)
Mehek14
  • Mehek14
combine like terms
Mehek14
  • Mehek14
\(\tt{8ats-2ats=6ats\\8a^2+6ats-2t^2s^2}\)
calculusxy
  • calculusxy
|dw:1444597636184:dw| Answer would be something like:
anonymous
  • anonymous
So ever many coefficients are the number there powered to?
calculusxy
  • calculusxy
\[\large \rm -2t^2s^2+2ats + 8a^2\]
Mehek14
  • Mehek14
if the same variables are multiplied to each other, then you get exponents ex \(\tt{t*t=t^2}\)
anonymous
  • anonymous
Oh Ok thank you
anonymous
  • anonymous
Wait you guys have two different answers
Mehek14
  • Mehek14
it's the same answers order doesn't matter
anonymous
  • anonymous
Oh my teacher said biggest number first
anonymous
  • anonymous
i see
calculusxy
  • calculusxy
degree of polynomials..
calculusxy
  • calculusxy
that's what i tried to do
Mehek14
  • Mehek14
\(\tt{8ats-2ats=6ats\\8a^2+6ats-2t^2s^2}\) I keep them in the order I multiply
calculusxy
  • calculusxy
|dw:1444598189445:dw|
calculusxy
  • calculusxy
@Mehek14 's right
anonymous
  • anonymous
What is it?
Mehek14
  • Mehek14
what is what?
anonymous
  • anonymous
Which is the answer his has 8 yours has 6
calculusxy
  • calculusxy
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mehek14 \(\tt{8ats-2ats=6ats\\8a^2+6ats-2t^2s^2}\) \(\color{#0cbb34}{\text{End of Quote}}\) you can order with degree of polynomials if you want
calculusxy
  • calculusxy
i made a silly mistake.
Mehek14
  • Mehek14
\[\large \rm -2t^2s^2+2ats + 8a^2\] \(\tt{8a^2+6ats-2t^2s^2}\) they are the same
Mehek14
  • Mehek14
oh wait you put 2ats
calculusxy
  • calculusxy
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mehek14 \[\large \rm -2t^2s^2+2ats + 8a^2\] \(\tt{8a^2+6ats-2t^2s^2}\) they are the same \(\color{#0cbb34}{\text{End of Quote}}\) not really...
anonymous
  • anonymous
Thanks again Guys
anonymous
  • anonymous
(2n^2+3by)(3n^2-by)?
anonymous
  • anonymous
How to i do them with exponents? @mehek14 @calculusxy
anonymous
  • anonymous
-3b^y^2+7bn^2y+6n^4?

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