1. Mehek14

use FOIL

2. calculusxy

|dw:1444596888643:dw|

3. calculusxy

I am not sure if this is correct ...

4. calculusxy

sorry. one moment

5. Mehek14

$$\tt{(t-sa)(9t+6sa)\\t*9t=9t^2\\-sa*9t=-9tsa\\t*6sa=6tsa\\-sa*6sa=-6sa^2\\9t^2-9tsa+6tsa-6sa^2}$$

6. Mehek14

you have to combine like terms

7. Mehek14

$$\tt{-9tsa+6tsa=-3tsa}$$

8. calculusxy

yes that's correct

9. freckles

|dw:1444597193897:dw|

10. calculusxy

@Mehek14 How did you change the font? I only know /rm and /scr

11. freckles

-sa*6sa=-6s^2a^2

12. Mehek14

i used \tt

13. freckles

|dw:1444597235822:dw|

14. calculusxy

@freckles YEAH!

15. Mehek14

$$\tt{9t^2-3tsa-6s^2a^2}$$

16. anonymous

So 9t^2-3tsa-6sa?

17. calculusxy

no use @Mehek14 's one.

18. anonymous

Thanks Guys your real life savers

19. anonymous

(4a-ts)(2a+2ts)? Its so confusing

20. anonymous

@Mehek14

21. Mehek14

$$\tt{(4a-ts)(2a+2ts)\\4a*2a=8a^2\\4a*2ts=8ats\\-ts*2a=-2ats\\-ts*2ts=-2t^2s^2}$$

22. Mehek14

combine like terms

23. Mehek14

$$\tt{8ats-2ats=6ats\\8a^2+6ats-2t^2s^2}$$

24. calculusxy

|dw:1444597636184:dw| Answer would be something like:

25. anonymous

So ever many coefficients are the number there powered to?

26. calculusxy

$\large \rm -2t^2s^2+2ats + 8a^2$

27. Mehek14

if the same variables are multiplied to each other, then you get exponents ex $$\tt{t*t=t^2}$$

28. anonymous

Oh Ok thank you

29. anonymous

Wait you guys have two different answers

30. Mehek14

it's the same answers order doesn't matter

31. anonymous

Oh my teacher said biggest number first

32. anonymous

i see

33. calculusxy

degree of polynomials..

34. calculusxy

that's what i tried to do

35. Mehek14

$$\tt{8ats-2ats=6ats\\8a^2+6ats-2t^2s^2}$$ I keep them in the order I multiply

36. calculusxy

|dw:1444598189445:dw|

37. calculusxy

@Mehek14 's right

38. anonymous

What is it?

39. Mehek14

what is what?

40. anonymous

Which is the answer his has 8 yours has 6

41. calculusxy

$$\color{#0cbb34}{\text{Originally Posted by}}$$ @Mehek14 $$\tt{8ats-2ats=6ats\\8a^2+6ats-2t^2s^2}$$ $$\color{#0cbb34}{\text{End of Quote}}$$ you can order with degree of polynomials if you want

42. calculusxy

43. Mehek14

$\large \rm -2t^2s^2+2ats + 8a^2$ $$\tt{8a^2+6ats-2t^2s^2}$$ they are the same

44. Mehek14

oh wait you put 2ats

45. calculusxy

$$\color{#0cbb34}{\text{Originally Posted by}}$$ @Mehek14 $\large \rm -2t^2s^2+2ats + 8a^2$ $$\tt{8a^2+6ats-2t^2s^2}$$ they are the same $$\color{#0cbb34}{\text{End of Quote}}$$ not really...

46. anonymous

Thanks again Guys

47. anonymous

(2n^2+3by)(3n^2-by)?

48. anonymous

How to i do them with exponents? @mehek14 @calculusxy

49. anonymous

-3b^y^2+7bn^2y+6n^4?