- anonymous

What is ax + z = aw − y , for a?

- jamiebookeater

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- Astrophysics

You can do the following \[z+y=aw-ax\] notice I added y on both sides and subtracted ax from both sides, now you can factor out an a.

- Astrophysics

Any idea how?

- anonymous

No

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Well yes

- Astrophysics

\[z+y=a(w-x)\] Notice since the left side both share an a

- Astrophysics

right side*

- anonymous

But how did you get z+y

- anonymous

and not -y-z

- Astrophysics

Oh I added +y instead of subtracting both sides by z just to make it look cleaner

- anonymous

But is subtracting both sides by z okay

- Astrophysics

Does that make sense? |dw:1444601291806:dw|

- Astrophysics

Yup, that's fine!

- Astrophysics

With what you did, you should get \[ax-aw=-z-y\]

- anonymous

but I got a = -y-z/x-w

- anonymous

is that right?

- Astrophysics

Yes!

- anonymous

really?!

- anonymous

it's not a = y+z/x-w

- Astrophysics

\[ax-aw=-z-y \implies a(x-w) = -z-y \implies a = \frac{ -z-y }{ x-w }\] that's perfect :)

- anonymous

??

- anonymous

How?

- Astrophysics

\[a = \frac{ -z-y }{ x-w }\] or \[a = \frac{ z+y }{ w-x }\] notice if you multiply the first equation by -1 you get the second equation, try to convince yourself by trying it

- anonymous

Do 2 negatives always = a positive in algebra?

- Astrophysics

yes :)

- anonymous

Even if they are not side by side

- anonymous

?

- Astrophysics

What do you mean

- anonymous

like -5-5

- anonymous

or is it only for variables?

- Astrophysics

Oh there you're just adding -(5+5) = -(10) = -10

- Astrophysics

Or subtracting by -5 how ever you like

- Astrophysics

-5-5 = -10

- anonymous

yeah

- Astrophysics

Unless you mean (-5)(-5) = 25

- anonymous

but how does -y-z = a positive?

- Astrophysics

-5x-5 = 25

- Astrophysics

(-y-z)*-1 = y+z

- anonymous

How did you get -1? Was it from factoring the two a's in the equation?

- Astrophysics

Oh no I was trying to show you that the first equation is same as the second, all you have to do is multiply by -1, algebra doesn't care :P
So the way I did your problem was basically the same way except I moved things differently, |dw:1444602003999:dw|

- anonymous

so it could come out either way and be right?

- Astrophysics

|dw:1444602123088:dw|

- Astrophysics

Yes

- Astrophysics

Now I'll do it again your way

- anonymous

k

- Astrophysics

|dw:1444602178558:dw|

- anonymous

Thank you so much!

- Astrophysics

Yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.