## anonymous one year ago I got the answer, I just dont know how. LOG help :(

1. anonymous

here to help m8

2. anonymous

$e^x-5=(1/e^4)^x+2$

3. anonymous

the x+2 is in the exponent with the x :/ Lol thanks

4. anonymous

u should see if tiger algebra will give the answer

5. anonymous

My teacher said something about how a power and power cancel, and her next step was this $e=e^-4(x+2)$

6. anonymous

just sayin retipe it here if u can and i will solve

7. anonymous

retype

8. anonymous

Whats tiger algebra?

9. anonymous

this is the website tiger-algebra.com

10. anonymous

11. anonymous

I have the answer, just dont know how

12. anonymous

13. anonymous

your

14. anonymous

didi u do it

15. anonymous

that website will show u the steps too m8

16. anonymous

It cant do what I needed :/

17. anonymous

damn what do u need m8

18. anonymous

sorry im part russian german and african american so im good in some things most i cant really do

19. Nnesha

is this ur question $\huge\rm e^{x-5}=(\frac{1}{e^4})^{x+2}$ @Melissa_Something

20. Nnesha

i don't know if the left side is e^{x-5} or e^(x) - 5

21. Nnesha

but right side you can move e^4 to the numerator just like we did on the previous post

22. Nnesha

is this ur question $\huge\rm e^{x-5}=(\frac{1}{e^4})^{x+2}$ OR $\huge\rm e^x-5 =(\frac{1}{e^4})^{(x+2)}$

23. Nnesha

here is an example $\huge\rm \frac{1}{x^{-m}}= x^{m}$ when we flip the fraction sign of the exponent would change so $\frac{1}{e^{4}}=?$

24. Nnesha

and yes e and ln cancel each other out $\large\rm e^{\ln x} = x$ $\large\rm \cancel{e^{\ln} x} = x$