I got the answer, I just dont know how. LOG help :(

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I got the answer, I just dont know how. LOG help :(

Mathematics
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here to help m8
\[e^x-5=(1/e^4)^x+2\]
the x+2 is in the exponent with the x :/ Lol thanks

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Other answers:

u should see if tiger algebra will give the answer
My teacher said something about how a power and power cancel, and her next step was this \[e=e^-4(x+2)\]
just sayin retipe it here if u can and i will solve
retype
Whats tiger algebra?
this is the website tiger-algebra.com
type in your browser
I have the answer, just dont know how
and post ypur answer
your
didi u do it
that website will show u the steps too m8
It cant do what I needed :/
damn what do u need m8
sorry im part russian german and african american so im good in some things most i cant really do
is this ur question \[\huge\rm e^{x-5}=(\frac{1}{e^4})^{x+2}\] @Melissa_Something
i don't know if the left side is e^{x-5} or e^(x) - 5
but right side you can move e^4 to the numerator just like we did on the previous post
is this ur question \[\huge\rm e^{x-5}=(\frac{1}{e^4})^{x+2}\] `OR` \[\huge\rm e^x-5 =(\frac{1}{e^4})^{(x+2)}\]
here is an example \[\huge\rm \frac{1}{x^{-m}}= x^{m}\] when we flip the fraction sign of the exponent would change so \[\frac{1}{e^{4}}=?\]
and yes `e` and `ln` cancel each other out \[\large\rm e^{\ln x} = x\] \[\large\rm \cancel{e^{\ln} x} = x\]

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