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anonymous
 one year ago
A perfectly spherical piece of metal is found at the bottom of a wishing well. The mass of the object is 1.3 kg and the radius is 0.25 m. What is its density? Answer in units of kg/m3.
009 (part 2 of 2) 10.0 points What would be its weight if it had the same volume and were made of pure gold? The density of pure gold is 19300 kg/m3. Answer in units of N.
anonymous
 one year ago
A perfectly spherical piece of metal is found at the bottom of a wishing well. The mass of the object is 1.3 kg and the radius is 0.25 m. What is its density? Answer in units of kg/m3. 009 (part 2 of 2) 10.0 points What would be its weight if it had the same volume and were made of pure gold? The density of pure gold is 19300 kg/m3. Answer in units of N.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0use density formula Density=Mass/volume the mass of it is 1.3k and the volume of it is .25 so 1.3/0.25= 5.2kg/m now cube that answer for final. For gold you have to work backwards. You have the density and you have the volume so plug them in. 19300kg/m^3=M/0.25 so multiply 19300 and 0.25 19300x0.25=? then uncube the answer to get final mass.

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1For the first, you first have to find the volume using the formula for the volume a sphere, the 0.25 m is only the radius. \(V_{sphere}=\dfrac{4}{3}\pi r^3\) For the second, once you have the mass, you have to multiply the the acceleration due to gravity. \(\sf F=ma\)
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