anonymous
  • anonymous
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form? a. 7x + 2y = –1 b. 7x + 2y = 1 c. 14x + 4y = –1 d. 14x + 4y = 1
Mathematics
schrodinger
  • schrodinger
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Vocaloid
  • Vocaloid
use the slope formula to calculate the slope between those two points
anonymous
  • anonymous
i still can't get it @Vocaloid
Vocaloid
  • Vocaloid
slope = m = (y2-y1)/(x2-x1)

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Vocaloid
  • Vocaloid
(x1,y1) = (-3,11) (x2,y2) = (1,-3)
Vocaloid
  • Vocaloid
just plug in the values for x1,x2,y1, and y2, then find the slope.
anonymous
  • anonymous
i got c @Vocaloid
Vocaloid
  • Vocaloid
show me how you got that answer
anonymous
  • anonymous
I'm on a ezam i can't show you i just need to know is that right I'm timed @Vocaloid
Vocaloid
  • Vocaloid
not allowed to help on exams, sorry :( best of luck~
anonymous
  • anonymous
here this helps me...
anonymous
  • anonymous
http://www.freemathhelp.com/combining-like-terms.html

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