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- anonymous

why is the square root of -1 equal to i

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- anonymous

why is the square root of -1 equal to i

- schrodinger

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- Nnesha

good question.

- anonymous

http://www.algebra.com/algebra/homework/Square-cubic-other-roots/Square-cubic-other-roots.faq.question.506680.html

- Vocaloid

I believe that's just how it's defined, isn't it?

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- anonymous

this should help

- mathstudent55

It's because mathematicians decided to define it that way.

- Nnesha

bec my teachers said so

- Vocaloid

what I meant to say was, mathematicians just decided to take the quantity sqrt(-1) and assign it the symbol i

- anonymous

ok

- anonymous

does this help @pocketpenguin1 ?

- anonymous

i understand that it is because the square root of -1 is not defined under real space due to the rules of square roots but i don't know how to write it in an algebraic form

- anonymous

not really @Houdini_Dragon

- anonymous

hmm ok one sec

- Vocaloid

can you give an example?

- anonymous

https://simple.wiktionary.org/wiki/square_root

- anonymous

how about now?

- Nnesha

it's cycle |dw:1444608366475:dw|

- anonymous

ooohhh i like it @Nnesha

- Nnesha

thanks.-,-

- anonymous

i understand more clearly now, you use a square root to find which number is being multiplied by itself in order to get the number under the square root symbol, but you can not multiply any number by itself to get -1, so \[\sqrt{-1}\] is in imaginary space

- anonymous

thank you

- anonymous

np medal?

- anonymous

nvm i am glad u got it and that is what matters

- Nnesha

for algebraic expression i guess i represent a variable
let's say we have 3i +4i = 7i it also depends on the statement hm

- anonymous

u can close this question now sense u understand........

- anonymous

how

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