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anonymous
 one year ago
A student adds 15.0 mL 2.00 M Acetic Acid and 15.0 mL 2.00 M NaOH. Determine the pH of the resulting solution.
Ka HC2H3O2 = 1.80E5
anonymous
 one year ago
A student adds 15.0 mL 2.00 M Acetic Acid and 15.0 mL 2.00 M NaOH. Determine the pH of the resulting solution. Ka HC2H3O2 = 1.80E5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This was my thought process. But it's saying that I have the answer incorrect by more than 10%

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2you have to use the concentrations as equilibrium, after the reaction (f any) has occured. The NaOH will neutralize the acetic acid, and you'll be left with 0.03 moles of acetate in 30 mL. so can just use the Kb and an eq. expression to find the pH

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@aaronq Okay, so would the equilibrium expression be Kc= [acetate] [OH]/ [acetic acid]??

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2nope, \(Acetate+H_2O\rightleftharpoons acetic~ acid+OH^\) \(K_B=\dfrac{[acetic~ acid][OH^]}{[acetate]}\)

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2oh, and \(\sf K_B=\dfrac{K_w}{K_A}\)
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