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anonymous

  • one year ago

If 5.00ml of 0.314M KOH is diluted to exactly 125mL with water, what is the concentration of the resulting solution?

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  1. aaronq
    • one year ago
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    It's a dilution, \(\sf M_1V_1=M_2V_2\) \(\sf (0.314~M)*(5~mL)=M_2*(5~mL+125~mL)\) the final molarity is \(\sf M_2\)

  2. whpalmer4
    • one year ago
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    @aaronq isn't it diluted to a total volume of 125 mL, not 125 mL added?

  3. aaronq
    • one year ago
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    oh right, sorry, i read the question as "diluted with exactly"

  4. anonymous
    • one year ago
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    so subtract 5 from 125?

  5. aaronq
    • one year ago
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    125 mL is the final volume, \(\sf (0.314~M)*(5~mL)=M_2*125~mL)\)

  6. anonymous
    • one year ago
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    ok looks like it works out correct into what the possible answers could be. Thank you again.

  7. aaronq
    • one year ago
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    np!

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