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|dw:1444621224019:dw|

so time period = 2pi/3

Substituting 2pi/3 for B we get
\[\large T=\frac{2 \pi}{\frac{2 \pi}{3}}=you\ can\ calculate\]

how would i do that

\[\large T=\frac{2 \pi \times3}{2 \pi}=?\]

well 2 pi can cancel eachother out right

Yes, your cancelling idea is correct.

so would it be t= 3/2pi

|dw:1444614205373:dw|

t=3

Correct.

would amplitude be 1/4

and by period do they mean time? if so then that cannot be determined

How do I find the period? 2pi and 1/4?

The period T was calculated to be 3 seconds.

how did we get that?

ohhhh okay! I see how that would be the answer thank you!

You're welcome :)

Please post your next question as a new question. Thank you.

alright:)