lol alright. I have this written out from before.
General Scheme:
\(\sf \large 1.\)First write and balance an equation for the process described.
So you have the chemical equation balanced (this is crucial because you need the stoichiometric coefficients).
\(\sf \large 2.\)Next, use the stoichiometric coefficients to find moles produced.
\(\sf \large 3.\) Set up a ratio using the species of interest, like so:
e.g. for a general reaction:
\(\sf \large \color{red}{a}A + \color{blue}{b}B \rightleftharpoons \color{green}{c}C\)
where upper case are the species (A,B,C), and lower case (a,b,c) are the coefficients ,
\(\sf \dfrac{n_A}{\color{red}{a}}=\dfrac{n_B}{\color{blue}{b}}=\dfrac{n_C}{\color{green}{c}}\)
From here you can isolate what you need.
For example: if you have 2 moles of B, how many moles of C can you produce?
solve algebraically: \(\sf\dfrac{2}{\color{blue}{b}}=\dfrac{n_C}{\color{green}{c}}\rightarrow n_C=\dfrac{2*\color{green}{c}}{\color{blue}{b}}\)
\(\sf \large 4.\) Solve
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you need to work with moles in stoichiometric problems, so convert the mass 3.5 g to moles of NaOH.
\(\sf moles=\dfrac{mass}{Molar~mass}\)
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once you found moles of sulfuric acid, convert to volume using: \(\sf molarity=\dfrac{moles}{Liters }\)