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lisa123

  • one year ago

f(x)=x^2+1, g(x)=x-2 (f+g)(t-8)

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  1. anonymous
    • one year ago
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    is there another function for t?

  2. lisa123
    • one year ago
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    no

  3. lisa123
    • one year ago
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    thats why im confused

  4. anonymous
    • one year ago
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    \[f(x)=x^2+1\\f(t-8)=(t-8)^2+1\] clean up with some algebra \[g(x)=x-2\\ g(t-8)=t-8-2\] clean up with some arithmetic then for \(f+g\) put a plus sign between them

  5. lisa123
    • one year ago
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    Thank you @satellite73 I got it right!

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