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JozelynW

  • one year ago

If the question says insert x=-5 into the equation 4^-x how would you do that? Would you say that 2 negatives equal a positive or just input -5

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  1. jim_thompson5910
    • one year ago
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    you would replace x with -5 so 4^(-x) = 4^(-(-5)) the two negatives cancel to form a positive which is why 4^(-(-5)) = 4^5

  2. anonymous
    • one year ago
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    yeah, it equal to positive

  3. JozelynW
    • one year ago
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    ok thank you i was just confused

  4. JozelynW
    • one year ago
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    what if its a positive number then?

  5. JozelynW
    • one year ago
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    @jim_thompson5910

  6. jim_thompson5910
    • one year ago
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    like if x = 9 ?

  7. jim_thompson5910
    • one year ago
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    if x = 9, then, \[\LARGE 4^{-x} = 4^{-9} = \frac{1}{4^9}\]

  8. JozelynW
    • one year ago
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    ok

  9. JozelynW
    • one year ago
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    what if x=1

  10. jim_thompson5910
    • one year ago
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    the negative exponent tells us to take the reciprocal of the base to make the exponent positive \[\LARGE x^{-k} = \frac{1}{x^k}\]

  11. JozelynW
    • one year ago
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    so for 2^x+3 what would x=3 be then

  12. jim_thompson5910
    • one year ago
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    \[\Large 2^x+3\] or \[\Large 2^{x+3}\] ??

  13. JozelynW
    • one year ago
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    the second 1

  14. JozelynW
    • one year ago
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    i think the answer would be 64

  15. jim_thompson5910
    • one year ago
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    \[\Large 2^{x+3} = 2^{3+3} = 2^6 = 64\] I agree

  16. JozelynW
    • one year ago
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    Ok thanks so much, I'm going to need more help later thou.

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