anonymous
  • anonymous
**Will give medals, super easy question** Find the vector https://gyazo.com/40f9a92a31ece57307589d029648e4ea
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jim_thompson5910
  • jim_thompson5910
have you learned about vector cross products?
anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
how far did you get when you tried out the problem? or were you stuck on how to get started?

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anonymous
  • anonymous
is it just the cross product?..
jim_thompson5910
  • jim_thompson5910
yes you apply the cross product of the two vectors
jim_thompson5910
  • jim_thompson5910
did you need help computing the cross product?
anonymous
  • anonymous
yes, how do i set this up
jim_thompson5910
  • jim_thompson5910
step 1) write out i,j,k along a horizontal row like this |dw:1444614782773:dw|
jim_thompson5910
  • jim_thompson5910
step 2) write each vector under the i,j,k (line up the corresponding elements) |dw:1444614829596:dw|
jim_thompson5910
  • jim_thompson5910
we will apply the determinant of this matrix |dw:1444614875046:dw| denoted by the vertical bars
jim_thompson5910
  • jim_thompson5910
to apply the determinant, copy the first two columns and move them to the right of the matrix |dw:1444614908976:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1444614942077:dw|
jim_thompson5910
  • jim_thompson5910
now we circle the diagonal elements like so |dw:1444614990848:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1444615040842:dw|
jim_thompson5910
  • jim_thompson5910
add up the results -14i + 2j + 6k
jim_thompson5910
  • jim_thompson5910
now we circle these diagonals |dw:1444615117544:dw|
jim_thompson5910
  • jim_thompson5910
Multiply out the elements in each subgroup |dw:1444615147629:dw|
jim_thompson5910
  • jim_thompson5910
add up the results 7k+(-6i)+4j = -6i+4j+7k
jim_thompson5910
  • jim_thompson5910
the last step is to subtract the two sums (first sum) - (second sum) = (-14i+2j+6k) - (-6i+4j+7k) (first sum) - (second sum) = -14i+2j+6k + 6i - 4j - 7k (first sum) - (second sum) = -8i - 2j - 1k So the cross product of the two vectors is <-8, -2, -1>
anonymous
  • anonymous
damn, thank you so much, can you help me with one more question though?
jim_thompson5910
  • jim_thompson5910
sure, go ahead

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