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anonymous

  • one year ago

**Will give medals, super easy question** Find the vector https://gyazo.com/40f9a92a31ece57307589d029648e4ea

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  1. jim_thompson5910
    • one year ago
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    have you learned about vector cross products?

  2. anonymous
    • one year ago
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    yes

  3. jim_thompson5910
    • one year ago
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    how far did you get when you tried out the problem? or were you stuck on how to get started?

  4. anonymous
    • one year ago
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    is it just the cross product?..

  5. jim_thompson5910
    • one year ago
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    yes you apply the cross product of the two vectors

  6. jim_thompson5910
    • one year ago
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    did you need help computing the cross product?

  7. anonymous
    • one year ago
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    yes, how do i set this up

  8. jim_thompson5910
    • one year ago
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    step 1) write out i,j,k along a horizontal row like this |dw:1444614782773:dw|

  9. jim_thompson5910
    • one year ago
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    step 2) write each vector under the i,j,k (line up the corresponding elements) |dw:1444614829596:dw|

  10. jim_thompson5910
    • one year ago
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    we will apply the determinant of this matrix |dw:1444614875046:dw| denoted by the vertical bars

  11. jim_thompson5910
    • one year ago
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    to apply the determinant, copy the first two columns and move them to the right of the matrix |dw:1444614908976:dw|

  12. jim_thompson5910
    • one year ago
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    |dw:1444614942077:dw|

  13. jim_thompson5910
    • one year ago
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    now we circle the diagonal elements like so |dw:1444614990848:dw|

  14. jim_thompson5910
    • one year ago
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    |dw:1444615040842:dw|

  15. jim_thompson5910
    • one year ago
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    add up the results -14i + 2j + 6k

  16. jim_thompson5910
    • one year ago
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    now we circle these diagonals |dw:1444615117544:dw|

  17. jim_thompson5910
    • one year ago
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    Multiply out the elements in each subgroup |dw:1444615147629:dw|

  18. jim_thompson5910
    • one year ago
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    add up the results 7k+(-6i)+4j = -6i+4j+7k

  19. jim_thompson5910
    • one year ago
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    the last step is to subtract the two sums (first sum) - (second sum) = (-14i+2j+6k) - (-6i+4j+7k) (first sum) - (second sum) = -14i+2j+6k + 6i - 4j - 7k (first sum) - (second sum) = -8i - 2j - 1k So the cross product of the two vectors is <-8, -2, -1>

  20. anonymous
    • one year ago
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    damn, thank you so much, can you help me with one more question though?

  21. jim_thompson5910
    • one year ago
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    sure, go ahead

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