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teller
 one year ago
Can someone help me please?
The functions u and w are defined as follows.
u(x)=2x+2
w(x)=3x+4
Find the value of u(w(−5))
teller
 one year ago
Can someone help me please? The functions u and w are defined as follows. u(x)=2x+2 w(x)=3x+4 Find the value of u(w(−5))

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plug 5 into the equation for W, and then take whatever value you get from that and plug it into U. Does that make sense?

teller
 one year ago
Best ResponseYou've already chosen the best response.0So it would first look like this ? u(5)=2(5)+2

teller
 one year ago
Best ResponseYou've already chosen the best response.0Not sure if that's correct or not.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No. So what you have here is a composite function. Whenever you have a composite function, you always solve the function that's next to X first and work your way outward. So for example, if we have f(g(x)), we solve g(x) first, and then we solve f(x) with the number that we got from g(x).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plug 5 into W and tell me what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 3(5)+4 is 11/5? \[W(5)=3(5)+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The (5) next do the W is not a specifically part of the equation. Whenever we have a function, let's say, F(x), we are saying that we have a function that is related in terms of x. Basically that further means that all of our variables in the equation are going to be in terms of X. For example, F(x)=x^2 or F(y)=y^2. It's not part of the equation, but it's a statement that helps clarify what variable our equation will use.

teller
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry I'm just confused now.....

teller
 one year ago
Best ResponseYou've already chosen the best response.0That confused me even more sorry....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're are dividing by 5 when you shouldn't be. It's not 5*W=3*5+4

teller
 one year ago
Best ResponseYou've already chosen the best response.0I'm not dividing I placed the equation like you wrote into the calculator and that's what I got...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes you are. \[W(5)=3(5)+4=19\] You said `19/5` which is dividing by a 5.

teller
 one year ago
Best ResponseYou've already chosen the best response.0That's what I got when I placed it into the calculator... I placed the exact same problem you did what calculator are you using because I'm using mathway,,,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is because Mathway is interpreting it as "W times 5" and that's not what the question is asking you. It's asking you to evaluate the equation at 5.

teller
 one year ago
Best ResponseYou've already chosen the best response.0So what do I do then would the final answer be 53? Or 53

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[W(5)=3(5)+4=19\] \[U(19)=2(19)+2=40\]

teller
 one year ago
Best ResponseYou've already chosen the best response.0Thank you just math isn't my strongest subject just doesn't stick with me and my teacher knows this but yet she doesn't give a flying f about what happens .She just tells us to do it on our own and expect us to grasp it without lessons or even videos really.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can understand that frustration. Even professors do that in college and it really bothers me. I would recommend visiting her before or after class and see if she's willing to help. Sometimes teachers won't do much in class, but if you go to see them oneonone and ask them for help, they'll be happy to. If she says she doesn't want to help you, then I would suggest going to administration or the principal to speak about it. And then find another math teacher before/after school to help you in the meantime.
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