Can Someone see if I did this right? The functions q and r are defined as follows. q(x)=-x+1 r(x)=-2x^2-1 Find the value of r(q(2) r(x)=-2(2)^2-1 is r=-9 replace the -9 in the other equation q(-9)=-9+1 which gave me 0.88889

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Can Someone see if I did this right? The functions q and r are defined as follows. q(x)=-x+1 r(x)=-2x^2-1 Find the value of r(q(2) r(x)=-2(2)^2-1 is r=-9 replace the -9 in the other equation q(-9)=-9+1 which gave me 0.88889

Mathematics
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I'm doing the same thing in math right now hold up.
Alright...
Okay so the q goes in the middle. It would be 1(2x^2-1)

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This is inverse functions right? I haven't started with exponents yet in the functions.
No it's Composition of two Functions
Oh I might have an answer sorry.
So yeah as far as I know all you have to do is put the one on the outside of 2x^2-1 and do the distributive property.
Here is an example from my H.W.
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Maybe this will help you.

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