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anonymous
 one year ago
When a 7.00g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 5.383 kJ·K–1, the temperature decreases by 0.300 K. Calculate the molar heat of solution of KCl.
anonymous
 one year ago
When a 7.00g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 5.383 kJ·K–1, the temperature decreases by 0.300 K. Calculate the molar heat of solution of KCl.

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Photon336
 one year ago
Best ResponseYou've already chosen the best response.0I think that this would have to be an endothermic reaction, because energy is absorbed. given by the fact hat the temperature decreases (tf < ti) meaning that heat was absorbed from the surroundings. \[7.0g KCl*(\frac{ mol }{ 75.0g }) = 0.09 mol, KCl\] \[q = mC \delta t \] not sure: \[\frac{ 5,383J }{ k (0.09) mol } = 57.9 kj*k ^{1}mol ^{1}\] q = 5.383jk*K^1

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0@Rushwr C = specific heat, while q = heat capacity right? so all you need to do is put q/moles that's what I thought for this question.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0had a feeling something was wrong, whoever gets the right answer to this please tag me. I want to see how this is done. @aaronq

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope, I've tried so many methods and all of them have been wrong so far haha. It should be in kj/mol.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg. it was as simple at (.3)(5.383) = 1.61 then divide by (7g/74.5mol) = 17.2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.017.2 kj/mol is the answer!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Heat absorbed by calorimeter = (heat capacity of calorimeter)(Tf  Ti) then divide by moles to get into the correct units

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for all the help!
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