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Photon336
 one year ago
@rushwr
Photon336
 one year ago
@rushwr

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Photon336
 one year ago
Best ResponseYou've already chosen the best response.04. A mixture of three gases has a pressure of 1380 mmHg at at 298 K. The mixture is analyzed and is found to contain 1.27 mol CO2, 3.04 mol CO, and 1.50 mol Ar. What is the partial pressure of Ar? a. 238 mm Hg b. 302 mm Hg c. 356 mm Hg d. 1753 mm Hg e. 8018 mm Hg

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1partial pressure = mole fraction * total pressure

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0\[total pressure = P_{t} \frac{ n_{GasA} }{ n_{total} } + P_{t}\frac{ n_{GasB} }{ n_{total} }.....n_{th,Gas}\]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Yep, partial pressure is equivalent to the total pressure multiplied by the mole fraction. \[Ar_{pressure} = P_{total}*\frac{ n_{Ar} }{ n_{total} } = \frac{ 1380mmHG }{ 760mmHG } *\frac{ 1.5mol_{Ar} }{ 5.81mol } = 0.468atm\] \[0.468 atm*(\frac{ 760mmHG }{ atm }) = 0.468*760 = 356 mmHG\] choice C.
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