anonymous one year ago Find the Derivative P(t) = 2*e^(-2e)^(2t) P prime (t) =

1. anonymous

By using the chain rule we get$P'(t)=2e^{(-2e)^{2t}}*-2e^{2t}*2$ It's a tedious one, but if you take it slow and break it down and it's not too bad. Chain rules within chain rules are always annoying

2. anonymous

yeah, it marked it as wrong ^^^^^

3. anonymous

Interesting.

4. zepdrix

If the exponent is really (-2t)^(2t), then this one is going to be be a lil more frustrating since the -2 is included lol

5. anonymous

yeah ^

6. anonymous

would we make a substitution? $u=-2e ^{2t}$

7. anonymous

See that's different than what you initially wrote :P

8. zepdrix

$\large\rm y=a^x$Recall that for differentiating exponentials:$\large\rm y'=a^x(\ln a)$So then,$\large\rm \frac{d}{dt}(-2e)^{2t}=(-2e)^{2t}\cdot \ln(-2e)\cdot (2)$Oh but then log of -2e isn't defined... Yah having a negative base is uhh... no bueno :U hmm

9. anonymous

yeaah, see i tried wolfphram alpha and it gave me an imaginary number???

10. zepdrix

Do you have a picture of the problem or something?

11. anonymous

12. zepdrix

Ugh :( Ya that's not what you wrote out on top -_-

13. anonymous

sorry i tried my best

14. zepdrix

Then Chris's derivative is correct :) We just gotta be careful with the brackets.

15. zepdrix

P(t)=2*e^(-2e^(2t)) P'(t)=2e(-2e^(2t))*(-2)e^(2t)*2 Try that maybe? :d Do you only get a limited number of "guesses"?

16. anonymous

I'm on my last one, but oh well only got 3 mins left

17. zepdrix

oh XD

18. zepdrix

oops i made a typo :O hopefully you caught that. umm the first part of it

19. zepdrix

P'(t)=2e^(-2e^(2t))*(-2)e^(2t)*2 there we go, forgot the carot on the first exponential >.<

20. anonymous

carot hahaaha

21. zepdrix

caret* :3 i dunno, whatever this thing is called "^" hehe

22. anonymous

oh haha it sorta looks like a carrot anyway

23. anonymous

ouch lol was a second late, when i hit submit it turned to 12 am :(

24. anonymous

automatically took me home

25. zepdrix

aw :P does it show solution?

26. zepdrix

lame t.t

27. anonymous

it doesn't :(

28. anonymous

im gonna get on it on office hours, thank guys!