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anonymous

  • one year ago

Find the Derivative P(t) = 2*e^(-2e)^(2t) P prime (t) =

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  1. anonymous
    • one year ago
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    By using the chain rule we get\[P'(t)=2e^{(-2e)^{2t}}*-2e^{2t}*2\] It's a tedious one, but if you take it slow and break it down and it's not too bad. Chain rules within chain rules are always annoying

  2. anonymous
    • one year ago
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    yeah, it marked it as wrong ^^^^^

  3. anonymous
    • one year ago
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    Interesting.

  4. zepdrix
    • one year ago
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    If the exponent is `really` (-2t)^(2t), then this one is going to be be a lil more frustrating since the -2 is included lol

  5. anonymous
    • one year ago
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    yeah ^

  6. anonymous
    • one year ago
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    would we make a substitution? \[u=-2e ^{2t}\]

  7. anonymous
    • one year ago
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    See that's different than what you initially wrote :P

  8. zepdrix
    • one year ago
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    \[\large\rm y=a^x\]Recall that for differentiating exponentials:\[\large\rm y'=a^x(\ln a)\]So then,\[\large\rm \frac{d}{dt}(-2e)^{2t}=(-2e)^{2t}\cdot \ln(-2e)\cdot (2)\]Oh but then log of -2e isn't defined... Yah having a negative base is uhh... no bueno :U hmm

  9. anonymous
    • one year ago
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    yeaah, see i tried wolfphram alpha and it gave me an imaginary number???

  10. zepdrix
    • one year ago
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    Do you have a picture of the problem or something?

  11. anonymous
    • one year ago
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  12. zepdrix
    • one year ago
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    Ugh :( Ya that's not what you wrote out on top -_-

  13. anonymous
    • one year ago
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    sorry i tried my best

  14. zepdrix
    • one year ago
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    Then Chris's derivative is correct :) We just gotta be careful with the brackets.

  15. zepdrix
    • one year ago
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    P(t)=2*e^(-2e^(2t)) P'(t)=2e(-2e^(2t))*(-2)e^(2t)*2 Try that maybe? :d Do you only get a limited number of "guesses"?

  16. anonymous
    • one year ago
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    I'm on my last one, but oh well only got 3 mins left

  17. zepdrix
    • one year ago
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    oh XD

  18. zepdrix
    • one year ago
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    oops i made a typo :O hopefully you caught that. umm the first part of it

  19. zepdrix
    • one year ago
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    P'(t)=2e^(-2e^(2t))*(-2)e^(2t)*2 there we go, forgot the carot on the first exponential >.<

  20. anonymous
    • one year ago
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    carot hahaaha

  21. zepdrix
    • one year ago
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    caret* :3 i dunno, whatever this thing is called "^" hehe

  22. anonymous
    • one year ago
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    oh haha it sorta looks like a carrot anyway

  23. anonymous
    • one year ago
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    ouch lol was a second late, when i hit submit it turned to 12 am :(

  24. anonymous
    • one year ago
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    automatically took me home

  25. zepdrix
    • one year ago
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    aw :P does it show solution?

  26. zepdrix
    • one year ago
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    lame t.t

  27. anonymous
    • one year ago
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    it doesn't :(

  28. anonymous
    • one year ago
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    im gonna get on it on office hours, thank guys!

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