anonymous
  • anonymous
Find the Derivative P(t) = 2*e^(-2e)^(2t) P prime (t) =
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
By using the chain rule we get\[P'(t)=2e^{(-2e)^{2t}}*-2e^{2t}*2\] It's a tedious one, but if you take it slow and break it down and it's not too bad. Chain rules within chain rules are always annoying
anonymous
  • anonymous
yeah, it marked it as wrong ^^^^^
anonymous
  • anonymous
Interesting.

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More answers

zepdrix
  • zepdrix
If the exponent is `really` (-2t)^(2t), then this one is going to be be a lil more frustrating since the -2 is included lol
anonymous
  • anonymous
yeah ^
anonymous
  • anonymous
would we make a substitution? \[u=-2e ^{2t}\]
anonymous
  • anonymous
See that's different than what you initially wrote :P
zepdrix
  • zepdrix
\[\large\rm y=a^x\]Recall that for differentiating exponentials:\[\large\rm y'=a^x(\ln a)\]So then,\[\large\rm \frac{d}{dt}(-2e)^{2t}=(-2e)^{2t}\cdot \ln(-2e)\cdot (2)\]Oh but then log of -2e isn't defined... Yah having a negative base is uhh... no bueno :U hmm
anonymous
  • anonymous
yeaah, see i tried wolfphram alpha and it gave me an imaginary number???
zepdrix
  • zepdrix
Do you have a picture of the problem or something?
anonymous
  • anonymous
zepdrix
  • zepdrix
Ugh :( Ya that's not what you wrote out on top -_-
anonymous
  • anonymous
sorry i tried my best
zepdrix
  • zepdrix
Then Chris's derivative is correct :) We just gotta be careful with the brackets.
zepdrix
  • zepdrix
P(t)=2*e^(-2e^(2t)) P'(t)=2e(-2e^(2t))*(-2)e^(2t)*2 Try that maybe? :d Do you only get a limited number of "guesses"?
anonymous
  • anonymous
I'm on my last one, but oh well only got 3 mins left
zepdrix
  • zepdrix
oh XD
zepdrix
  • zepdrix
oops i made a typo :O hopefully you caught that. umm the first part of it
zepdrix
  • zepdrix
P'(t)=2e^(-2e^(2t))*(-2)e^(2t)*2 there we go, forgot the carot on the first exponential >.<
anonymous
  • anonymous
carot hahaaha
zepdrix
  • zepdrix
caret* :3 i dunno, whatever this thing is called "^" hehe
anonymous
  • anonymous
oh haha it sorta looks like a carrot anyway
anonymous
  • anonymous
ouch lol was a second late, when i hit submit it turned to 12 am :(
anonymous
  • anonymous
automatically took me home
zepdrix
  • zepdrix
aw :P does it show solution?
zepdrix
  • zepdrix
lame t.t
anonymous
  • anonymous
it doesn't :(
anonymous
  • anonymous
im gonna get on it on office hours, thank guys!

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