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anonymous
 one year ago
I need some help with the last question of an exercise thats too long to type out so I will attach a picture.
The answers for all the questions before are:
(i) = a+4d; a+14d
(iii) This is the one I need help with and I know that the answer is 2.4 but I can't get there.
anonymous
 one year ago
I need some help with the last question of an exercise thats too long to type out so I will attach a picture. The answers for all the questions before are: (i) = a+4d; a+14d (iii) This is the one I need help with and I know that the answer is 2.4 but I can't get there.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am sorry I made a mistake the answer is 2.5. still need help though

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Have you finished part ii ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1good, then simply take the ratio of second term and first term : \[\dfrac{a+4d}{a}\] plugin \(d = \dfrac{3}{8}a\) and simplify

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1good, then simply take the ratio of second term and first term : \[\text{common ratio}=\dfrac{a+4d}{a}\] plugin \(d = \dfrac{3}{8}a\) and simplify

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1notice that \(a\) cancels out

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1plugging \(d = \dfrac{3}{8}a\) gives \[\text{common ratio}=\dfrac{a+4d}{a} = \dfrac{a+4*\dfrac{3}{8}a}{a}=1+\dfrac{3}{2}=?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok! So the a's cross out to 1 which is added?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Yes, we can factor out \(a\) and cancel it with the \(a\) in the bottom : \[\text{common ratio}=\dfrac{a+4d}{a} = \dfrac{a+4*\dfrac{3}{8}a}{a}=\dfrac{a\left(1+4*\dfrac{3}{8}\right) }{a}=1+\dfrac{3}{2}=?\]
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