anonymous
  • anonymous
I need some help with the last question of an exercise thats too long to type out so I will attach a picture. The answers for all the questions before are: (i) = a+4d; a+14d (iii) This is the one I need help with and I know that the answer is 2.4 but I can't get there.
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
I am sorry I made a mistake the answer is 2.5. still need help though
ganeshie8
  • ganeshie8
Have you finished part ii ?
anonymous
  • anonymous
Yes

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ganeshie8
  • ganeshie8
good, then simply take the ratio of second term and first term : \[\dfrac{a+4d}{a}\] plugin \(d = \dfrac{3}{8}a\) and simplify
anonymous
  • anonymous
Ah OK thanks.
ganeshie8
  • ganeshie8
good, then simply take the ratio of second term and first term : \[\text{common ratio}=\dfrac{a+4d}{a}\] plugin \(d = \dfrac{3}{8}a\) and simplify
ganeshie8
  • ganeshie8
notice that \(a\) cancels out
anonymous
  • anonymous
so I get 1.5a ?
ganeshie8
  • ganeshie8
plugging \(d = \dfrac{3}{8}a\) gives \[\text{common ratio}=\dfrac{a+4d}{a} = \dfrac{a+4*\dfrac{3}{8}a}{a}=1+\dfrac{3}{2}=?\]
anonymous
  • anonymous
Oh ok! So the a's cross out to 1 which is added?
ganeshie8
  • ganeshie8
Yes, we can factor out \(a\) and cancel it with the \(a\) in the bottom : \[\text{common ratio}=\dfrac{a+4d}{a} = \dfrac{a+4*\dfrac{3}{8}a}{a}=\dfrac{a\left(1+4*\dfrac{3}{8}\right) }{a}=1+\dfrac{3}{2}=?\]

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