anonymous
  • anonymous
will give medal and fan Secx+tanx/secx +tanx-cosx
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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campbell_st
  • campbell_st
well use what you know sec = 1/cos tan = sin/cos so the problem is \[\frac{1}{\cos(x)} + \frac{\frac{\sin(x)}{\cos(x)}}{\frac{1}{\cos(x)}} + \frac{\sin(x)}{\cos(x)} - \cos(x)\] a lot of common denominators here... but start by simplifying the fraction
anonymous
  • anonymous
Ok
anonymous
  • anonymous
how would i simplfy

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anonymous
  • anonymous
plz help
anonymous
  • anonymous
\[\frac{ \frac{ \sin(x) }{ \cos(x) } }{ \frac{ 1 }{ \cos(x) } }\]
anonymous
  • anonymous
You need to simplify that.
anonymous
  • anonymous
sinx
anonymous
  • anonymous
correct now write out you problem again and determine a common denominator
anonymous
  • anonymous
cosx
anonymous
  • anonymous
is it cos x
anonymous
  • anonymous
yes
anonymous
  • anonymous
so is that my answer
anonymous
  • anonymous
no..rewrite the equation with the common denominator
anonymous
  • anonymous
\[\cos /\sin /\cos/1\]
anonymous
  • anonymous
1+sin(x)cos(x)+sin(x)-cos(x^2) all over cos(x)...
anonymous
  • anonymous
now i just simplfy
anonymous
  • anonymous
yes..
anonymous
  • anonymous
1+sin(x)cos(x)+sin(x)-cos(x^2) this is all you have to simplify
anonymous
  • anonymous
sin2(x)+sin(x)cos(x)+sin(x)
anonymous
  • anonymous
is that right
anonymous
  • anonymous
Very good but you can break out the sin(x)
anonymous
  • anonymous
ok
anonymous
  • anonymous
sin(x)(sin(x)+cos(x)+1)
anonymous
  • anonymous
Good job

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