A projectile is fired with initial velocity of v0 feet per second. The projectile can be pictured as being fired from the origin into the first quadrant, making an angle (theta) with the positive x-axis, as shown in the figure. If there is no air resistance, then at t seconds the coordinates of the projectile (in feet) are x = (v0t)(cos(theta)) and y = -16t^2 + (v0t)(sin(theta)). Suppose a projectile leaves the gun at 100 ft/sec and theta = 60.
f) show that y = ((-16sec^2(theta))/v0^2)(x^2) + tan(theta)

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