shaleiah
  • shaleiah
Quadratic formula (Medal) (Fan)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
shaleiah
  • shaleiah
+16** not 6
shaleiah
  • shaleiah
@tanya123
shaleiah
  • shaleiah
the values of a,b,c

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anonymous
  • anonymous
`Quadratic Formula`: \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] Note that c will be -5 when we move the 11 over to the other side. P lug in your values and solve carefully :) Let me know if you get stuck
anonymous
  • anonymous
5* not -5
shaleiah
  • shaleiah
\[\frac{ -3\pm \sqrt{-3^2-4(5)(-5)} }{ 2(5) }\]
anonymous
  • anonymous
It should be 4(5)(5), but yes, that is correct so far. Make sure that when you evaluate -3^2, you evaluate it as (-3)^2 so that the negative is inside the square. :) Continue to simplify it and let me know what you get
anonymous
  • anonymous
Oh and there should be a positive 3 in front, sorry. Because you have -b but b = -3, so -(-3)=3
shaleiah
  • shaleiah
\[\frac{ 3\pm \sqrt{109} }{ 10 }\]
anonymous
  • anonymous
I believe it should be -91 on the inside. \[\frac{3 \pm \sqrt{(-3)^2-4(5)(5)}}{10} = \frac{3 \pm \sqrt{9-100}}{10}\]
triciaal
  • triciaal
|dw:1446353214104:dw|
anonymous
  • anonymous
Yes, @triciaal that is what I put.
triciaal
  • triciaal
@shaleiah do you see how to apply the formula? b^2 - 4 a c is called the discriminant and can be used to determine the nature of the roots.
shaleiah
  • shaleiah
Yes, thank you.
triciaal
  • triciaal
|dw:1446353980821:dw|
triciaal
  • triciaal
you are welcome

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