Given 2w = -7z. Solve for w

- anonymous

Given 2w = -7z. Solve for w

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- anonymous

Given 2w = -7z. Solve for w

- anonymous

Divide both sides by 2 and you will have w :)

- anonymous

Assuming that your problem is 2w = -7z. I'm not sure what you put in the first post.

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## More answers

- anonymous

|dw:1446360673388:dw|

- anonymous

The answer should be -7z/2. When I divided both sides by 2 I got -3.5. :(

- anonymous

You forgot the z. When you divide by 2, the z doesn't go away.
w = (-7/2)z = -3.5z

- anonymous

According to the practice test answers - it is supposed to be -7z / 2 and I have been trying to figure out how this answer comes out

- anonymous

Get a calculator - plug in (-7/2) and let me know what you get.

- anonymous

-3.5

- anonymous

Exactly -- they're the same thing. The solution left it in a fraction, but -3.5z is the same thing. Both are correct answers.
However, if your teacher wants you to leave it in a fraction, then leave it as (-7/2)z. If your teacher says simplify as a decimal, then simplify it to -3.5z. If they don't specify, then they more than likely won't care what form it's in, okay?

- anonymous

Great.. My last problem unsolved is solve : 20 -15 / (-5). (The answer should be 23)

- anonymous

Okay, so I'm assuming then that the format is:
\[\large 20-\frac{15}{(-5)}\]
Sometimes it can get confusing when it's typed in simple text. If what I have is correct, then yes, 23 is the answer.
Whenever we divide by a negative, it's the same as if the negative is on top, ok? So
\[\huge 20-\frac{ -15 }{ 5 }=20--3=20+3=23\]
Make sense?

- anonymous

The following formula relates three qualities: distance (d), rate (r), and time (t) d=rt
Solve this for t (t=d/r) how do you write this out?

- anonymous

It's already written out for you.
So if you have d = rt, you see that the r and t are multiplied. How do you get rid of the r on the right side?

- anonymous

Hint: it's the same process that we used for your first question all the way at the top

- anonymous

dividing both sides by 2?

- anonymous

t would = d/r

- anonymous

travel = distance / rate

- anonymous

b) if the distance is d=300 miles and the rate is r=60 mph, find the time, t
(5 hours)

- anonymous

and c) If the distance is d = 250 miles and the time is t = 4.5 hours, find the rate, r.
( 55.56 mph)

- anonymous

for b). It gives you d and r. You already said that t = d/r so just plug it in :)
for c). You need to solve for r instead! So instead of getting t by itself, you need to get r by itself.

- anonymous

Ok with b) I got 300 divided by 60 = 5 ( t = d/r)

- anonymous

Yep! Sounds good to me

- anonymous

For c how do I write this one out d=rt? 250=55.56*4.5

- anonymous

We said that d = rt, so to get r by itself, we must divide by t this time.
Therefore, r = d/t. Plug in the two numbers it gave you for d and t and you'll have your rate!

- anonymous

d = 250 / t 4.5 = 55.55
r = 55.56

- anonymous

r = 55.56 mph

- anonymous

Yep!! :)

- anonymous

Thank you so very much. I have finished the practice test. I have to submit it to the teacher. After this I will take the unit test Monday.

- anonymous

Good luck! :)

- anonymous

OH, well I have a new problem not sure how to do it is |dw:1446366800377:dw|

- anonymous

After submitting to the dropbox of the practice test, the unit test is not that bad until the very last problem.

- anonymous

The options are x = -12/y, x = -12y, x = -3/4y and x = -4y / 3
I am going with x = -12/y

- anonymous

Ok, I got that one wrong. Which should the correct answer have been?

- UnkleRhaukus

3x / 4 = -y
multiply both sides by 4
3x = -4y
divide both sides by 3
x = . . .

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