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For this one, I ran a combin again.. but Im not sure.. combin (7,3) = 35 Im not sure if there is actually more to this.
is it actually a total of 9 divisions?
no, only 3 divisions, one division per country choose 3 managers from 7, combin(7,3) is correct :)
THANKS again !
wait, does the order matter here?
ah I dont think so...
I did think about that..
so I should always ask that I suppose.
no i dont think order matters
A in country 1 , B in country 2, C in country 3 B in country 1, A in country 2 , C in country 3 these both are different, right?????
nope order doesnt matter in this case
Well I do have another question similar.. "Suppose 15 students are lined up outside a classroom waiting to get in. You want to determine how many different ordered ways they can enter the classroom, one at a time. Check all of the correct methods you could use to determine how many different ordered ways they can enter the classroom." This looks like order matters.,
or wait.. it does ask.. "how many different ordered ways"
so order does matter hey.
exactly my point ABC, BCA, ACB, BAC.... are all different
hmm read the question twice
ok, so it's 210 .. permut(7,3)
They just want the numbers of ways order is not mentioned
are you sure RVC? Quote "How many different ordered ways could the three new heads be appointed?"
for the 2nd one, yes order matters. so toal how many ways?
are there other methods other than permutation to find how many different ordered ways? or permutation the only way? say given multiplication rule, or factorials.. and combos.
this looks like a factorial would also give us an answer.. being that they are ALL going in.
15 students can enter in 15different ways
it looks like 15! would give us the answer too
15! is correct. paermuation is just one of the many ways. like you can use permutation for 2nd problem, permute (15,15) = 15!
all d best :)
thanks guys.. I think I'm good then.