madmerc
  • madmerc
Find the solution of 3 sqrt x+5 = -9 and determine if it is an extraneous solution x = 4 ; not extraneous x = 4 ; extraneous x = 0 ; extraneous x = 0 ; not extraneous
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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madmerc
  • madmerc
\[3\sqrt{x + 5}=-9\] is what the question looks like
madmerc
  • madmerc
@freckles please help I don't understand what this is
baru
  • baru
well we can solve this equation..take 3 to rhs, square both sides blah blah... but look at the equation carefully, we cannot get a negative value for square root. although we can solve for x and find a number, it is 'extraneous'

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madmerc
  • madmerc
? i don't understand what that means. the solution is extraneous? but what does x equal?
baru
  • baru
ok...lets first solve for x \(\\\sqrt{x+5} = -3 \\square~ both ~sides\\ x+5=9\\x=4\)
baru
  • baru
followed?
madmerc
  • madmerc
yeah okay ! so it's the second one, x = 4 extraneous
baru
  • baru
do you understand why its extraneous?
madmerc
  • madmerc
something to do with the solution right like its not proven right
baru
  • baru
yep, so we have \( \sqrt{x+5}=-3\) do you know any number whose square root is negative?
madmerc
  • madmerc
no...
baru
  • baru
because there isnt... this equation actually has no solution. but we have somehow solved for x using correct mathematical operations. that is why the solution is called 'extraneous'

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