Angel_Kitty12
  • Angel_Kitty12
P(B)=2/3 P(A)=2/5 P(A or B)=11/20 Find P(A|B)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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freckles
  • freckles
do you know another way to write P(A|B)?
freckles
  • freckles
Also do you recall: \[P(A \text{ or } B)=P(A)+P(B)-P(A \text{ and } B) \\ \text{ and so } P(A \text{ and } B)=P(A)+P(B)-P(A \text{ or } B)\]
Angel_Kitty12
  • Angel_Kitty12
P(A|B)= P(A)‱P(B)-P(A and B)

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Angel_Kitty12
  • Angel_Kitty12
I believe so
freckles
  • freckles
shouldn't this be it: \[P(A|B)=\frac{P(A \text{ and } B)}{P(B)}\]
Angel_Kitty12
  • Angel_Kitty12
Oh that as well yes
Angel_Kitty12
  • Angel_Kitty12
I'm a bit confused with the formulas
freckles
  • freckles
never seen the first one you mentioned are you sure that is right?
freckles
  • freckles
I definitely seen the one I mentioned
Angel_Kitty12
  • Angel_Kitty12
I don't think I'm right but that is a formula for dependent overlap but I think I mixed my formulas up
Angel_Kitty12
  • Angel_Kitty12
No wait IM WRONG I WROTE IT WRONG DISREGARD 😅😅 sorry
freckles
  • freckles
k well try using the one I mentioned try using both the ones I mentioned
freckles
  • freckles
like you find P(A and B) first using the first one I mentioned
freckles
  • freckles
then you can plug in that result a long with the number given for P(B) to find P(A|B)
freckles
  • freckles
so first: do you think you can find P(A and B) using: \[P(A \text{ and } B)=P(A)+P(B)-P(A \text{ or } B)?\]
Angel_Kitty12
  • Angel_Kitty12
Okay so the fraction forms would go in as 2/3+2/5-11/20 correct?
freckles
  • freckles
correct which equals
Angel_Kitty12
  • Angel_Kitty12
I'm a bit confused here though. Do I add the fractions even thought they do not have the same denominator?
freckles
  • freckles
to add/subtract fractions you need to find a common denominator first
Angel_Kitty12
  • Angel_Kitty12
Okay that's what confused me. Let me try..
Angel_Kitty12
  • Angel_Kitty12
31/60
freckles
  • freckles
k know use the second formula we mentioned you just found P(A and B) and you were already given P(B) plug into the formula for P(A|B)
Angel_Kitty12
  • Angel_Kitty12
I cannot see the second formula you have given
freckles
  • freckles
\[P(A|B)=\frac{P(A \text{ and } B)}{P(B)}\] you cannot see this one?
Angel_Kitty12
  • Angel_Kitty12
Wait yes I can now never mind
Angel_Kitty12
  • Angel_Kitty12
So it would kinda look like X=31/60/2/3 correct?
freckles
  • freckles
\[P(A|B)=\frac{\frac{31}{60}}{\frac{2}{3}} \text{ or can be written as } \frac{31}{60} \cdot \frac{3}{2}\]
Angel_Kitty12
  • Angel_Kitty12
So the answer would be 93/120 or 0.775 correct?
freckles
  • freckles
yes 93/120 can be reduced \[\frac{31}{60 } \cdot \frac{3}{2} =\frac{3}{60 } \cdot \frac{31}{2} =\frac{1}{20} \cdot \frac{31}{2}=\frac{31}{40}\] so 31/40 or .775
Angel_Kitty12
  • Angel_Kitty12
Or 31/40 if simplified
Angel_Kitty12
  • Angel_Kitty12
Okay I understand now. Thank you so much!

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