Disregard.

- pooja195

Disregard.

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- chestercat

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- OdesseyMoore

Ok

- pooja195

Ok post your problem :)

- OdesseyMoore

It's 1/2 n =3/4

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## More answers

- pooja195

You had the answer of 3/2 which was initially correct.

- OdesseyMoore

I never gave a answer

- pooja195

It was on your previous post.

- OdesseyMoore

I need help solving the problem so I can write a justification

- pooja195

Ah ok you wrote
"If It's 1/2 n =3/4 then n=3/2"

- OdesseyMoore

I could stay focused on my previous post

- OdesseyMoore

Couldn't

- pooja195

lol its alright ok im going to explain it :)

- OdesseyMoore

Ok

- pooja195

\[\huge~\rm~ \frac{ 1 }{ 2 }n=\frac{ 3 }{ 4 }\]

- pooja195

Any ideas on what the first step is?

- OdesseyMoore

To find n

- pooja195

\[\huge~\rm~ \frac{ 1 }{ 2 }n(2)=\frac{ 3 }{ 4 }(2)\]
We multiply by the reciprocal

- pooja195

N cancels out
\[n=? \]
do the solving... 3/4 x 2=?

- OdesseyMoore

3/6

- anonymous

no

- pooja195

You did something wrong.

- OdesseyMoore

1/3

- pooja195

Hold on
You should have gotten 6/4
2 x 3 /4
6/4

- pooja195

Now you can simplify that to get the correct answer :)

- pooja195

Need help?

- pooja195

@OdesseyMoore are you there?

- pooja195

Divide the numerator and denominator by 2
\[\huge~\rm~\frac{ 6/2=? }{ 4/2=? }\]

- imqwerty

u put 2 '=' signs

- imqwerty

clearly wrong

- pooja195

That is a way of getting the fraction.

- imqwerty

ok

- anonymous

What's next?

- OdesseyMoore

3/2

- anonymous

x = ?

- pooja195

Good :)

- pooja195

@OdesseyMoore That is the justification for the problem

- imqwerty

n=9/6
is also correct

- OdesseyMoore

Thank you now there one more mind helping

- pooja195

It's correct but it would be wrong because fractions can be simplified.

- imqwerty

yea sure np B)

- pooja195

@OdesseyMoore yes :)

- anonymous

You're welcome @OdesseyMoore

- OdesseyMoore

0=2(r-3)+4

- pooja195

0=2(r−3)+4
0=(2)(r)+(2)(−3)+4(Distribute)

- anonymous

im starting to suspect cheating here. Why so many questions? You should of been able to understand it now after 3+ problems.

- imqwerty

i agree with @V_for_Vengeance

- anonymous

I sense someone is helping someone cheat. Which is against CoC.
Law 3, chapter 4 line 8

- imqwerty

maybe this is his/her test

- pooja195

Seriously? If you guys have nothing nice to say don't say it quit spamming ever single post this user asks a question on.

- pooja195

If you want to continue spamming then leave

- pooja195

@OdesseyMoore Can you distribute?
0=2(r−3)+4
\[\huge~\rm~0=(2)(r)+(2)(−3)+4(Distribute)\]

- Zale101

Are you familiar with distributing @odesseymoore ? We can go over that for you.

- OdesseyMoore

A little bit

- imqwerty

@OdesseyMoore please tell ur approach to the prblm
and the point where ur stuck
this will help us explain u better

- OdesseyMoore

This Is also justification

- Zale101

I agree with @imqwerty . If you try the problem and work it out here, we can see the mistake your making and we can pint it out for you.

- Zale101

point*

- imqwerty

:)

- Zale101

It would be better to show your attempts. For ex. Post a problem after you work it out. And post your work here.

- imqwerty

it will also save time

- Zale101

Yep^

- OdesseyMoore

Never mind my mom is home she'll help me finish thank you guys for helping me

- Zale101

This is your question:
0=2(r−3)+4
Try to solve it, then post your work here.

- imqwerty

try the prblm as much as u can
if ur not getting it then also u keep doin it ..try diff ways...don't think that ur wasting ur time in doin it cuz the time is not wasted its utilized
after trying out the prblm so many times when u get a single hint u get the answer at once

- Zale101

Always try solving your questions before asking them. It helps and saves time! :)

- Zale101

Anytime
All thanks to everyone who've helped you!

- imqwerty

B)

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