Orb
  • Orb
The L-shaped wire in the previous exercise (for Example 30.1) is now smoothed out with a quarter arc. In other words, the wire runs from y = +∞ to the point (0,b), then joined by a circular arc with radius b (centered at the point P(b,b)), continue on from (b,0) to x = +∞, with b = 0.4m. What is the magnetic field B (magnitude) at the point P(b,b) if the current is 2.0A? I have no idea how to get started. What should be the first step?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Orb
  • Orb
Here is the L-shaped wire (attached)
1 Attachment
anonymous
  • anonymous
vector S is an inversion of theta, but collinear.
anonymous
  • anonymous
orthogonal to b

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anonymous
  • anonymous
run the conductance along x, until ring O...? Distribution of charge is proportional to material density and conductivity...i think.
anonymous
  • anonymous
one sec.
anonymous
  • anonymous
P(r)theta.. and a relation to ds Let me grab a pencil
inkyvoyd
  • inkyvoyd
I see this problem and I would just like to let you know that I'm scared.
Orb
  • Orb
Um, I'm not following, but I do know this has something to do with the Biot-Savart Law.
anonymous
  • anonymous
The rotation is along one axis, point O. The conductance is along the vector (r). At P(theta) it looks like the charge is then dispersed. As long as I is the rotation vector along with d(s)? I can't tell very well where the direction of vector s is pointing..
anonymous
  • anonymous
sSorry, Have to go back to work.
Orb
  • Orb
Alright, thanks for the help! But I still dont know how to get started T_T
anonymous
  • anonymous
start with seeing the rotation as a propagation point of a charge density, carried along the wire. Does that help?
anonymous
  • anonymous
The ring is spinning, if I'm not mistaken, and it looks like the vector (s) which is a magnitude is point orthogonal to (r). What do you know about orthogonal charges along a wire?
anonymous
  • anonymous
|dw:1446426618761:dw| The drawing is poor, but if you try to find the wavelength of 2A along the wire, based on theta and rotations it might help.
Orb
  • Orb
I don't think we've been through that in our class (yet). I'll attach the reading that was before the question (it may help).
1 Attachment
anonymous
  • anonymous
(.04,b)->(b,b) = f:(s,theta) element of By Let me read the notes..
anonymous
  • anonymous
the point of distance of B is the area you want to calculate, using the integral provided.
anonymous
  • anonymous
treat the area of set (B) as 2pi parallel to I.
anonymous
  • anonymous
sorry, parallel to O
anonymous
  • anonymous
then work from 4pi to R squared.
anonymous
  • anonymous
Ok, I have to go now. I hope that helped frame the problem at least!
Orb
  • Orb
Thanks!
Orb
  • Orb
I'll try!
Orb
  • Orb
How should I draw the picture where the ring with the L-shaped wire is "smoothed out with a quarter arc"? I think that's the hardest part of this question. ;_;

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