Integral of 1/(x+1)^2. This feels like it should be simple, but I can't put my finger on the answer...
Stacey Warren - Expert brainly.com
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I was thinking of product ruling it with (x+1)^-2 as u and dx as dv... but it doesn't seem like that'll go anywhere. The natural log antiderivat thing might work, but I haven't done it with a denominator to a power before...
No, see what I wrote above?
Do you agree with what I wrote?
When (x+1) is your variable that makes no difference because dx would =du if you set u=x+1, and thus you can just treat x+1 as a single variable, or if you like you can perform that u sub anyway