The sum of three consecutive even integers is -72. What is the least of these numbers?
Stacey Warren - Expert brainly.com
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Think as the consecutive numbers as this (x+1)+(x+2)+(x+3)= -72
Solve the equation and then find x
So would look like this
Read my previous post and x would be your answer
Because the consecutive numbers have to be even so you would have to do x + (x + 2) + (x + 4) because then you would be getting all consecutive even numbers.
Sorry I am wrong they are supposed to be even listen to Lexie
are you sure x is the answer... remember you have
x, x+2 and x + 4
Isn't "least" referring to greatest negative value?
@denonakavro we are doing even consecutive so x is even
and count by 2's ( x-2, x, x + 2 )
x + (x +2) + (x + 4) = -72; afterwards you would add all the xs together and add the numbers and get 3x + 6 = -72 then afterwards you would subtract 6 from both sides and end up with 3x = -78 then you would divide 3 on both sides and end with x = -26 but that is the greatest factor like @jaeuni had said so you would have to take -26 and add 4 to it
using the equation in the posts...
the user has used
1st even integer as x
2nd even integer as x + 2
3rd even integer as x + 4
then recommended you solve for x
this is a valid method
to me, least will be the integer closest to zero...
@campbell_st lol my bad, it was phrased awkwardly but yes, when I said "greatest" I also meant the value closest to zero - it was in response to someone saying that the answer was x