give me some Graphing Quadratic Functions,

- Adi3

give me some Graphing Quadratic Functions,

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- schrodinger

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- Adi3

@IrishBoy123

- IrishBoy123

you can play with the sliders
https://www.desmos.com/calculator/p69hhmoyxe

- IrishBoy123

slider b is fun 🌝

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## More answers

- Adi3

i want to practice graphing

- imqwerty

graph this-\[4x^2-2x+2=0\]
then graph this-\[2x^2-x+1=0\]

- Adi3

graph without using calculator

- Adi3

so i might not be able to post the answer

- imqwerty

ok jst try it
post a rough sketch :)

- Adi3

ok, i will be back after 30 minutes, i have to do my chem hw ok?

- Adi3

20 minutes not 30

- Adi3

ok?

- imqwerty

okay B)

- Adi3

stay here ok

- imqwerty

sry i have to go to arctic to hunt penguins so i won't be here ):

- Adi3

really that kind off joke

- Adi3

do you know the intersection thing in quad

- imqwerty

plot the graphs there are more jokes to come :)

- imqwerty

wym?

- Adi3

intersection of quadratics with lines and with other quadratics

- Adi3

for example

- Adi3

sketch the graph of f(x) = x +2 on the grid
sketch the grapgh of f(x) = x^2
find the points of intersections algebrically

- Adi3

like that

- imqwerty

oh ok yes :)

- Adi3

ask me stuff like that

- imqwerty

u want me to ask u ques based on quadratic eqs?

- Adi3

no, on solving using perfect squares, i am week in perfect squares i need help in that

- imqwerty

ok solve this quad eq using the perfect square technique-
\[4x^2+9x+5=0\]

- Adi3

but remember i am just in 10th

- imqwerty

ik :)

- Adi3

how do you solve it

- Adi3

4x^2 + 9x + = 5 then?

- Adi3

will you reply till tmrw

- imqwerty

ok jst follow these simple steps-
if u have any quad eq like this-\[ax^2+bx+c=0\]

- imqwerty

just divide all over by a u get this-\[x^2 +\frac{ bx }{ a }+\frac{ c }{ a }=0\]

- imqwerty

tell ok if ur following the steps
ok?

- Adi3

we did not learn that yet

- imqwerty

i didn't do anything special i jst divided

- Adi3

we do this 4x^2 + 9x + = 5
than we find a number that multiply to 9 and adds to 5

- imqwerty

this is not the perfect square method this is the factorization method
which method do u wanna learn

- Adi3

square root method

- imqwerty

u mean the perfect square method right? :)

- Adi3

yeah

- Adi3

lets just do with x^2 + 2x + 4 = 0 too make it easy

- imqwerty

ok

- imqwerty

now we have to make a perfect square

- imqwerty

the perfect square should be of this form-\[(x+p)^2=q\]

- Adi3

ok, how

- Adi3

my bad completing the square method, sorry

- imqwerty

1st u take the constant term(the term without x) onthe other side
2nd u should focus on the coefficient of x^2 term
if the coefficient is not 1 and is some other number say n
then u just divide all over by n
ok?
in this case the coefficient is 1
so we don't have to worry
3rd u focus upon the term which is having x in it
lets say the term is kx
u multiply divide this term by 2
then u get this- 2(k/2)(x)
we lets apply these steps in our ques
\[x^2+2x+4=0\]
\[x^2+2x=-4\]
2nd coefficient of x=1
so no need to divide and all
3rd we see the x term it is 2x divide and multiply it by 2 u get this-
\[x^2+2(\frac{ 2 }{ 2 })(x)=-4\]
now we observe it carefully
we see that this thing is like
\[x^2 + \left( \frac{ 2 }{ 2 }\right)^2+2\left( \frac{ 2 }{ 2 } \right)(x)=-4\]
the only problem is that it doesn't have (2/2)^2 in it
so we add (2/2)^2 on both sides
we get this-
\[x^2 + 2\left( \frac{ 2 }{ 2 } \right)(x)+\left( \frac{ 2 }{ 2 } \right)^2=-4+\left( \frac{ 2 }{ 2 } \right)^2\]\[\left( x+\frac{ 2 }{ 2 } \right)^2=-4+1\]\[(x+1)^2=-3\]
this equation has no real roots cause the square of any number can't be negative

- Adi3

ok, since I understand this, lets do graph using vertex form and factored form, ok

- Adi3

ok?

- imqwerty

:) ok

- imqwerty

what do u knw about these forms

- Adi3

15 minute study break

- imqwerty

x'D ok

- Adi3

@imqwerty

- Adi3

@imqwerty

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