Adi3
  • Adi3
give me some Graphing Quadratic Functions,
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Adi3
  • Adi3
@IrishBoy123
IrishBoy123
  • IrishBoy123
you can play with the sliders https://www.desmos.com/calculator/p69hhmoyxe
IrishBoy123
  • IrishBoy123
slider b is fun 🌝

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More answers

Adi3
  • Adi3
i want to practice graphing
imqwerty
  • imqwerty
graph this-\[4x^2-2x+2=0\] then graph this-\[2x^2-x+1=0\]
Adi3
  • Adi3
graph without using calculator
Adi3
  • Adi3
so i might not be able to post the answer
imqwerty
  • imqwerty
ok jst try it post a rough sketch :)
Adi3
  • Adi3
ok, i will be back after 30 minutes, i have to do my chem hw ok?
Adi3
  • Adi3
20 minutes not 30
Adi3
  • Adi3
ok?
imqwerty
  • imqwerty
okay B)
Adi3
  • Adi3
stay here ok
imqwerty
  • imqwerty
sry i have to go to arctic to hunt penguins so i won't be here ):
Adi3
  • Adi3
really that kind off joke
Adi3
  • Adi3
do you know the intersection thing in quad
imqwerty
  • imqwerty
plot the graphs there are more jokes to come :)
imqwerty
  • imqwerty
wym?
Adi3
  • Adi3
intersection of quadratics with lines and with other quadratics
Adi3
  • Adi3
for example
Adi3
  • Adi3
sketch the graph of f(x) = x +2 on the grid sketch the grapgh of f(x) = x^2 find the points of intersections algebrically
Adi3
  • Adi3
like that
imqwerty
  • imqwerty
oh ok yes :)
Adi3
  • Adi3
ask me stuff like that
imqwerty
  • imqwerty
u want me to ask u ques based on quadratic eqs?
Adi3
  • Adi3
no, on solving using perfect squares, i am week in perfect squares i need help in that
imqwerty
  • imqwerty
ok solve this quad eq using the perfect square technique- \[4x^2+9x+5=0\]
Adi3
  • Adi3
but remember i am just in 10th
imqwerty
  • imqwerty
ik :)
Adi3
  • Adi3
how do you solve it
Adi3
  • Adi3
4x^2 + 9x + = 5 then?
Adi3
  • Adi3
will you reply till tmrw
imqwerty
  • imqwerty
ok jst follow these simple steps- if u have any quad eq like this-\[ax^2+bx+c=0\]
imqwerty
  • imqwerty
just divide all over by a u get this-\[x^2 +\frac{ bx }{ a }+\frac{ c }{ a }=0\]
imqwerty
  • imqwerty
tell ok if ur following the steps ok?
Adi3
  • Adi3
we did not learn that yet
imqwerty
  • imqwerty
i didn't do anything special i jst divided
Adi3
  • Adi3
we do this 4x^2 + 9x + = 5 than we find a number that multiply to 9 and adds to 5
imqwerty
  • imqwerty
this is not the perfect square method this is the factorization method which method do u wanna learn
Adi3
  • Adi3
square root method
imqwerty
  • imqwerty
u mean the perfect square method right? :)
Adi3
  • Adi3
yeah
Adi3
  • Adi3
lets just do with x^2 + 2x + 4 = 0 too make it easy
imqwerty
  • imqwerty
ok
imqwerty
  • imqwerty
now we have to make a perfect square
imqwerty
  • imqwerty
the perfect square should be of this form-\[(x+p)^2=q\]
Adi3
  • Adi3
ok, how
Adi3
  • Adi3
my bad completing the square method, sorry
imqwerty
  • imqwerty
1st u take the constant term(the term without x) onthe other side 2nd u should focus on the coefficient of x^2 term if the coefficient is not 1 and is some other number say n then u just divide all over by n ok? in this case the coefficient is 1 so we don't have to worry 3rd u focus upon the term which is having x in it lets say the term is kx u multiply divide this term by 2 then u get this- 2(k/2)(x) we lets apply these steps in our ques \[x^2+2x+4=0\] \[x^2+2x=-4\] 2nd coefficient of x=1 so no need to divide and all 3rd we see the x term it is 2x divide and multiply it by 2 u get this- \[x^2+2(\frac{ 2 }{ 2 })(x)=-4\] now we observe it carefully we see that this thing is like \[x^2 + \left( \frac{ 2 }{ 2 }\right)^2+2\left( \frac{ 2 }{ 2 } \right)(x)=-4\] the only problem is that it doesn't have (2/2)^2 in it so we add (2/2)^2 on both sides we get this- \[x^2 + 2\left( \frac{ 2 }{ 2 } \right)(x)+\left( \frac{ 2 }{ 2 } \right)^2=-4+\left( \frac{ 2 }{ 2 } \right)^2\]\[\left( x+\frac{ 2 }{ 2 } \right)^2=-4+1\]\[(x+1)^2=-3\] this equation has no real roots cause the square of any number can't be negative
Adi3
  • Adi3
ok, since I understand this, lets do graph using vertex form and factored form, ok
Adi3
  • Adi3
ok?
imqwerty
  • imqwerty
:) ok
imqwerty
  • imqwerty
what do u knw about these forms
Adi3
  • Adi3
15 minute study break
imqwerty
  • imqwerty
x'D ok
Adi3
  • Adi3
@imqwerty
Adi3
  • Adi3
@imqwerty

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