some.random.cool.kid
  • some.random.cool.kid
When factored, the trinomials x2 − 12x + 35 and x2 − 2x − 35 have one binomial factor in common. What is this factor? x − 7 x + 7 x − 5 x + 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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some.random.cool.kid
  • some.random.cool.kid
@sammixboo @sleepyhead314 @freckles @robtobey @rvc @ParthKohli @Michele_Laino
some.random.cool.kid
  • some.random.cool.kid
this is just the first one i have quite a few more.
some.random.cool.kid
  • some.random.cool.kid
@AlexandervonHumboldt2 @kropot72 @ikram002p @Jaynator495 @Jesstho.-. @just_one_last_goodbye

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some.random.cool.kid
  • some.random.cool.kid
@Mehek14 @Data_LG2
some.random.cool.kid
  • some.random.cool.kid
@inkyvoyd
Maddy1251
  • Maddy1251
(5 + -1X)(7 + -1X) = 0 is the first polynomial I have factored.
some.random.cool.kid
  • some.random.cool.kid
ok
some.random.cool.kid
  • some.random.cool.kid
so now distribute each correct?
Maddy1251
  • Maddy1251
the second one is (x+5)(x-7)
Maddy1251
  • Maddy1251
No. You look for a common factor they have.
some.random.cool.kid
  • some.random.cool.kid
oh alright afterwards I just do this for each until they match a common factor?
Maddy1251
  • Maddy1251
Yup. Factor each polynomial out until you find them in the (x+n)(x-n) form, or however they need to be factored, and you will find a common factor for each.
Maddy1251
  • Maddy1251
x2 − 12x + 35 = (x-5)(x-7)
Maddy1251
  • Maddy1251
Looks like x-7 is your common factor.
some.random.cool.kid
  • some.random.cool.kid
oh my gosh I just realized that there are two separate equations ok that makes much more sense now.
some.random.cool.kid
  • some.random.cool.kid
and thank you very much.
Maddy1251
  • Maddy1251
Haha yeah! :-) You're welcome!
some.random.cool.kid
  • some.random.cool.kid
ok well that helped didn't realize that think you can help with another bit different this time but same concept.
Maddy1251
  • Maddy1251
Yes.
some.random.cool.kid
  • some.random.cool.kid
ok thanks What is one factor of 20x2 + 6x − 8? 2x − 1 4x + 2 5x − 4 10x − 1 I was thinking that I can factor by two each? although that wouldn't work for the second half.
Maddy1251
  • Maddy1251
Well, We want to have a factor that can go into 20, 6, and 8. A does this, B does this, C and D do not.
Maddy1251
  • Maddy1251
So that helps eliminate half our answers.
Maddy1251
  • Maddy1251
Do you understand what I mean by that?
some.random.cool.kid
  • some.random.cool.kid
uh so that factor would be 2? and I am not sure about the second half with the minus. all i know is that they all factor by two.
Maddy1251
  • Maddy1251
That's true. Correct. Well I can figure that out for you if you want it.
Maddy1251
  • Maddy1251
( 2x − 1)(10x+8) 20x^2+16x-10x-8. Does this equal the equation?
some.random.cool.kid
  • some.random.cool.kid
yes I would like to learn it, im not sure why it is left over. Please explain.
Maddy1251
  • Maddy1251
\[20x ^{2}+6x-8\]
some.random.cool.kid
  • some.random.cool.kid
hmm :o i see it now.
Maddy1251
  • Maddy1251
Yeah!
Maddy1251
  • Maddy1251
See why it isn't D either?
Maddy1251
  • Maddy1251
Because we need 10x+1. Not 10x-1.
Maddy1251
  • Maddy1251
I just did the factor concept to find our first factor.
some.random.cool.kid
  • some.random.cool.kid
OH i was about t say I was confused because i thought the 20 divided by 2 becomes 10 but if it needs to + sign I guess that makes sense... during any of this do I have to flip signs?
Maddy1251
  • Maddy1251
No.. the only time I know about flipping signs is with inequalities, when you divide/multiply with negative numbers.
Maddy1251
  • Maddy1251
But remember 10/6 and 10/4 doesn't give whole numbers.
some.random.cool.kid
  • some.random.cool.kid
ahhhh so since this needs a + sign does this meanyour left with 4x + 2?
Maddy1251
  • Maddy1251
No, your answer is A.
some.random.cool.kid
  • some.random.cool.kid
yeah thats what i was confused about because the 10 feeds a decimal.
some.random.cool.kid
  • some.random.cool.kid
:O please explain im lost.
Maddy1251
  • Maddy1251
Remember the factor of \[20x ^{2}+6x-8=(2x-1)(10x+8)\]
Maddy1251
  • Maddy1251
2 goes into 20, 6, and 8 in such a good manner. 4 only goes into 20 and 8.
Maddy1251
  • Maddy1251
And our second factor won't be (10x+8), or we would get a different polynomial
some.random.cool.kid
  • some.random.cool.kid
ahah missed that part.
Maddy1251
  • Maddy1251
That's why 2x-1 works so well.
Maddy1251
  • Maddy1251
Yeah! They tried getting you with answer choice D.
Maddy1251
  • Maddy1251
It's their trick .
some.random.cool.kid
  • some.random.cool.kid
I know funny thing is I almost fell for it to then figured I would go on openstudy to check. thanks. I have only a few more mind helping? I might have to pst a new thread though because OS sometimes crashes when the page is to long from the lag.
Maddy1251
  • Maddy1251
It's okay, it happens. :-) I would love to help, and go ahead and start a new thread and mention me in it.
Maddy1251
  • Maddy1251
While you do that, I will grab a bite to eat.

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