anonymous
  • anonymous
What are the area and perimeter of the sector of the circle shown? C is the center. Use an EXACT answer with fractions
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@atreyu6s3x6
anonymous
  • anonymous
anonymous
  • anonymous
okay do you know the formula for a cector? area and perimeter/?

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anonymous
  • anonymous
nope
anonymous
  • anonymous
@atreyu6s3x6
anonymous
  • anonymous
i have to hurry on this one 2, only have a certain time limit
anonymous
  • anonymous
\[\theta/360 *\pi*r^2\]
anonymous
  • anonymous
and yea i have to go so lets finish...so 90/360=0.25 0.25*pi*3^2 0.25*pi*9 simplify
anonymous
  • anonymous
that is your area
anonymous
  • anonymous
7.065 is area? @atreyu6s3x6
anonymous
  • anonymous
is that using the exact answer in fractions? @atreyu6s3x6
anonymous
  • anonymous
A=7.068 without roundong
anonymous
  • anonymous
@MyNameIsNemo can you help her?
anonymous
  • anonymous
im sorry i have to go now............. i have class now... D: im sorry
MyNameIsNemo
  • MyNameIsNemo
uhm maybe possibly? .-.
anonymous
  • anonymous
@MyNameIsNemo we found area now we need perimeter
MyNameIsNemo
  • MyNameIsNemo
meh okie i can try
anonymous
  • anonymous
okay thanks @MyNameIsNemo
MyNameIsNemo
  • MyNameIsNemo
idk the equation for the perimeter .-. @AlexandervonHumboldt2 might help you though, hes very smart and helpful see if you can get him
anonymous
  • anonymous
@AlexandervonHumboldt2
anonymous
  • anonymous
@AlexandervonHumboldt2
anonymous
  • anonymous
we found area, now we need perimeter
AlexandervonHumboldt2
  • AlexandervonHumboldt2
for P use formula 2*pi*r*C/360=2*3.14*3*90/360=4.71
AlexandervonHumboldt2
  • AlexandervonHumboldt2
where C is central angle
anonymous
  • anonymous
so is 4.71 my answer for perimeter? @AlexandervonHumboldt2
AlexandervonHumboldt2
  • AlexandervonHumboldt2
yeah if they mean arc length by perimeter
anonymous
  • anonymous
yes, can you help me with one more fast question?
AlexandervonHumboldt2
  • AlexandervonHumboldt2
ok

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