Clarence
  • Clarence
My friend got 1/15 whereas I got 15/16 for the following series:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Clarence
  • Clarence
\[\sum_{n=1}^{\infty} \frac{ 1^{n} }{ (-15)^{n-1} }\]
anonymous
  • anonymous
it can't really be \(1^n\) can it?
Clarence
  • Clarence
It unfortunately is :/

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anonymous
  • anonymous
lol ok you are right your friend is wrong
Clarence
  • Clarence
Just a guess? :P
anonymous
  • anonymous
no not a guess, you can do it in your head
Clarence
  • Clarence
You're obviously way more educated than I am then
anonymous
  • anonymous
whats is \(1-(-\frac{1}{15})\)?
anonymous
  • anonymous
aka \[1+\frac{1}{15}\]?
Clarence
  • Clarence
16/15?
anonymous
  • anonymous
yes of course and the reciprocal of \(\frac{16}{15}\) is?
Clarence
  • Clarence
15/16?
anonymous
  • anonymous
no not 15/16? but rather 15/16 !!! how hard was that?
Clarence
  • Clarence
Fair enough! I guess I'm just so used to the teacher saying to do questions a certain way that I didn't think about that, thanks!
anonymous
  • anonymous
i am not that educated, this is easy is all for example \[\sum\left(\frac{2}{3}\right)^n\] \[1-\frac{2}{3}=\frac{1}{3}\] the reciprocal of \(\frac{1}{3}\) is \(3\) finished math teaches like to make things harder than they actually are

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