anonymous
  • anonymous
You roll two fair dice, one green and one red. (b) Find P(5 on green die and 3 on red die). (c) Find P(3 on green die and 5 on red die). (d) Find P((5 on green die and 3 on red die) or (3 on green die and 5 on red die)). please help and explain with this... I'm stuck..
Mathematics
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SOLVED
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chestercat
  • chestercat
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Nnesha
  • Nnesha
i'm not good at probability question but ehhh let me try it one dice = 6 sides you can get 5 only one time right and same with 3 = there is only possibility to get 3 on each dice |dw:1446522296655:dw|
anonymous
  • anonymous
i appreciate that you're still trying to help (:
Nnesha
  • Nnesha
P(5G and 3R) \[\rm \color{green}{\frac{ 1 }{ 6}}\] possibility to get 5 \[\rm \color{red}{\frac{ 1 }{ 6 }}\] possibility to get 3 on one die

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More answers

anonymous
  • anonymous
yea.. so 2/24 ?
Nnesha
  • Nnesha
and since both dice are independent so multiply both fraction
Nnesha
  • Nnesha
now we should multiply them not add.
anonymous
  • anonymous
oh so... 2/36?
Nnesha
  • Nnesha
\[\rm (\color{green}{\frac{ 1 }{ 6}})*(\color{red}{\frac{1}{6}})\] multiply numerator *numerator and denominator * denominator
anonymous
  • anonymous
1/36..?
Nnesha
  • Nnesha
looks good
anonymous
  • anonymous
think i got it.. thanks !
anonymous
  • anonymous
mmmm what about the last one..?
Nnesha
  • Nnesha
for last one would do same thing first set up the fraction for `P((5 on green die and 3 on red die)` and for `(3 on green die and 5 on red die))`. and then add both result
Nnesha
  • Nnesha
the*
anonymous
  • anonymous
so its 1/36 +1/36 ?
Nnesha
  • Nnesha
right
anonymous
  • anonymous
thin i got it ... thank so much !
Nnesha
  • Nnesha
np :=))

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