Pagen13
  • Pagen13
Identify the vertex, axis of symmetry, maximum or minimum, and domain and range of the function. F(x)=2(x+9)^2-4
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jchick
  • jchick
What have you done so far?
Pagen13
  • Pagen13
I don't understan any of it...
campbell_st
  • campbell_st
well the vertex form of the parabola is \[y = a(x - h)^2 + k\] (h, k) is the vertex... so what is the vertex in your equation... just match the information

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Pagen13
  • Pagen13
(9,4)
campbell_st
  • campbell_st
close your equation is \[y = 2(x - (-9))^2 + (-4)\] this may make it easier.... you need to check
Pagen13
  • Pagen13
So (-9,-4)
campbell_st
  • campbell_st
great... next, the line of symmetry is the h value in the vertex... and it will be in the form x = ..? any thoughts...
campbell_st
  • campbell_st
or to make it easier... the line of symmetry is the x value in the vertex
Pagen13
  • Pagen13
So -9^2?
campbell_st
  • campbell_st
you need the values from the vertex... you said the vertex is (-9, -4) so the line of symmetry comes from the vertex and is x = -9 does that make sense...?
Pagen13
  • Pagen13
Oh okay yeah
campbell_st
  • campbell_st
the max or min value also comes from the vertex.. in your question, the parabola is concave up... so the minimum value is the y-value in the vertex... so what do you think the minimum is y = ??
Pagen13
  • Pagen13
y=-4
campbell_st
  • campbell_st
that's correct... the curve looks like this |dw:1446578016113:dw|
campbell_st
  • campbell_st
now the domain, you can input any x value into the curve... so the domain is all real x. the range goes from the minimum value to positive infinity... so you need to just work out how to write the domain and range
campbell_st
  • campbell_st
hope it helped.
campbell_st
  • campbell_st
so in summary vertex (-9, -4) line of symmetry: x = -9 minimum value: y = -4 domain: all real x range y greater than or equal to -4
Pagen13
  • Pagen13
Thank You!!!

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