deerhunter15
  • deerhunter15
Geometry! Please HELP ME!!!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
deerhunter15
  • deerhunter15
deerhunter15
  • deerhunter15
deerhunter15
  • deerhunter15
@Nnesha last one, need help, and fast because its due by 2:30, and having trouble with the whole question because its confusing.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
whats the problem?
deerhunter15
  • deerhunter15
in the attatched files...
anonymous
  • anonymous
there are two witch one
deerhunter15
  • deerhunter15
deerhunter15
  • deerhunter15
the one i just posted is the one
anonymous
  • anonymous
what grade is this?
deerhunter15
  • deerhunter15
10th
anonymous
  • anonymous
by im in 6th
Nnesha
  • Nnesha
alright then i'm not good at geometry but lets try it out. we need to use midpoint and slope formula to prove DE is parallel to AC
deerhunter15
  • deerhunter15
Ok
Nnesha
  • Nnesha
|dw:1446580151082:dw|
Nnesha
  • Nnesha
|dw:1446580309182:dw| B point is at the origin that's why i put (0,0) order pair now to find find D midpoint use the midpoint formula \[(\frac{ x_1 +x_2 }{ 2 } +\frac{y_1+y_2}{2})\]
Nnesha
  • Nnesha
use point B and A to find midpoint D B(0,0) A(0,a)
deerhunter15
  • deerhunter15
0,D
Nnesha
  • Nnesha
|dw:1446580617770:dw| first find midpoint D and E then we can find slope of both line to prove they are parallel
deerhunter15
  • deerhunter15
how do you work m_1 and M_2
Nnesha
  • Nnesha
m_1 means first midpoint which is D and m_2 is 2nd mid point which is E
Nnesha
  • Nnesha
do you mean D mid point is (0,D ) ??
deerhunter15
  • deerhunter15
Idk but i think maybe it is
Nnesha
  • Nnesha
use point A and B to find midpoint D formula is \[(\frac{ x_1 +x_2 }{ 2 }, \frac{y_1+y_2}{2})\] x's and y's values are (0,0(0,a)
Nnesha
  • Nnesha
and then use point A and C to find midpoint E A(0,a) C(c,0)
deerhunter15
  • deerhunter15
|dw:1446581005508:dw|
deerhunter15
  • deerhunter15
so point e would be like 1,0
Nnesha
  • Nnesha
we can't assume E (1,0) it can be (2,0) we need to use given order pair
Nnesha
  • Nnesha
use point A and B to find midpoint D formula is \[(\frac{ x_1 +x_2 }{ 2 }, \frac{y_1+y_2}{2})\] x's and y's values are (0,0(0,a) \[(\color{ReD}{x_1} ,y_1)(\color{red}{x_2},y_2) \rightarrow (0,0)(0,a)\]
Nnesha
  • Nnesha
plugin
deerhunter15
  • deerhunter15
D (0,a/2)
Nnesha
  • Nnesha
yes right now find point E use point C and A
deerhunter15
  • deerhunter15
e( C/2,0)
Nnesha
  • Nnesha
ah ye that's correct sorry i meant to say point C and B in my last comment good job!
Nnesha
  • Nnesha
now we have to use the slope formula to find slope of DE and slope of point AC
Nnesha
  • Nnesha
\[\huge\rm slope =\frac{ y_2 -y_1}{ x_2 -x_1}\]|dw:1446581793811:dw|
Nnesha
  • Nnesha
use the D and E point to find slope of DE and use C and A point to find slope of AC
Nnesha
  • Nnesha
let me know if you don't understand that ^^
deerhunter15
  • deerhunter15
I dont understand a^2-0^1 -------- 0^2-c^1
Nnesha
  • Nnesha
ohh it's not square y_1 means first one
Nnesha
  • Nnesha
like A(0,a) C(c,0) so \[\rm (x_1 ,y_1)(x_2 ,y_2) \rightarrow (0,a)(c,0)\]
deerhunter15
  • deerhunter15
is that the answer?
Nnesha
  • Nnesha
|dw:1446582619883:dw|
Nnesha
  • Nnesha
no we have to prove DE is parallel to AC in order to prove we should find slope of both equation
Nnesha
  • Nnesha
use the slope formula to find slope of AC \[\huge\rm \frac{ y_2 -y_1 }{ x_2 -x_1 }\] x and y's values are (0,a)(c,0)
Nnesha
  • Nnesha
look at the drawing i've posted above x_1 = 0 x_2 =c y_1 = a y_2=0
deerhunter15
  • deerhunter15
....im still not understanding and I have to go in about 10-20 minutes
Nnesha
  • Nnesha
alright what part you don't understand ?
deerhunter15
  • deerhunter15
we are like just dividing a by c
Nnesha
  • Nnesha
just find the sl0pe of both lines that's it
deerhunter15
  • deerhunter15
the slope of D and E will be half of A and C
Nnesha
  • Nnesha
welll what about the sign it should be like this \[(0,a)(c,0 ) \rightarrow \frac{ 0-a }{ c-0 }\]
Nnesha
  • Nnesha
no no we are proving DE and AC are parallel lines and parallel lines have the same slope
deerhunter15
  • deerhunter15
erm
deerhunter15
  • deerhunter15
so is it A=C
deerhunter15
  • deerhunter15
@Nnesha
Nnesha
  • Nnesha
slope of both lines supposed to be the same
Nnesha
  • Nnesha
definition of parallel lines: they both have the same slope
Nnesha
  • Nnesha
read the direction prove DE and AC are parallel lines `state ` the coordinates and show all work so you need slope of AC and slope of DE to prove they both are parallel lines
Nnesha
  • Nnesha
\[(0,a)(c,0 ) \rightarrow \frac{ 0-a }{ c-0 }\] solve this
Nnesha
  • Nnesha
In other words simplify what would be the final slope ?
Nnesha
  • Nnesha
remember if line is decreasing you will get negative slope line increasing = positive slope
Nnesha
  • Nnesha
for the 2nd part just use distance formula to prove DE is half of AC \[\large\rm \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2}\]
Nnesha
  • Nnesha
D(0,a/2) C (c/2 ,0)

Looking for something else?

Not the answer you are looking for? Search for more explanations.