anonymous
  • anonymous
please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1446582043145:dw|
anonymous
  • anonymous
Add
stuck-help
  • stuck-help
this is confusing are dividing each 1 by x+1

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More answers

anonymous
  • anonymous
|dw:1446582208718:dw|
anonymous
  • anonymous
You're suppose to add them and get a single fraction as the answer
anonymous
  • anonymous
The answer is suppose to be x^3 +x^2 +2x+1/x^2 +x+1
mathstudent55
  • mathstudent55
|dw:1446582003962:dw|
mathstudent55
  • mathstudent55
Start inside the rectangle. Write x as x/1 and find a common denominator. |dw:1446582056388:dw|
mathstudent55
  • mathstudent55
|dw:1446582099144:dw|
anonymous
  • anonymous
This is confusing. Is this algebra 1?
mathstudent55
  • mathstudent55
Do you follow so far?
anonymous
  • anonymous
I think
anonymous
  • anonymous
do you just distribute and then add
mathstudent55
  • mathstudent55
We are only adding the denominator inside the rectangle for now. We needed a common denominator, so we used x + 1 as the common denominator. Now we actually add the two fractions.
mathstudent55
  • mathstudent55
|dw:1446582371093:dw|
mathstudent55
  • mathstudent55
Yes, you are correct. Distribute the left numerator to get x^2 + x. Then add to the other numerator, 1.
mathstudent55
  • mathstudent55
Now we need to add x to that complex fraction. Before we actually do the addition, we can simplify the complex fraction on the right side, and make it a simple fraction.
mathstudent55
  • mathstudent55
|dw:1446582533933:dw|
anonymous
  • anonymous
then would you make x^2 +x+1 the LCD
mathstudent55
  • mathstudent55
Do you understand how the complex fraction was simplified?
mathstudent55
  • mathstudent55
Correct.
mathstudent55
  • mathstudent55
|dw:1446582635510:dw|
mathstudent55
  • mathstudent55
|dw:1446582721380:dw|
anonymous
  • anonymous
okay what about when the problem is|dw:1446583054536:dw|
mathstudent55
  • mathstudent55
Now just combine the two x's in the numerator.
anonymous
  • anonymous
I'm confused on how to do that @mathstudent55

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