Vector help! Stuff like this https://gyazo.com/1c432a147c3cf41b2b2865f1dcf886e8

- anonymous

Vector help! Stuff like this https://gyazo.com/1c432a147c3cf41b2b2865f1dcf886e8

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- Kenshin

Expand the brackets out, so if u = [-4,-6], v=[1,-3], -2u = [-2*-4, -2*-6]， and 4v = [4*1, 4*-3], then add -2u and 4v together.

- anonymous

its A rite?

- Kenshin

yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Want to stay and help me with this online assignment for medal or do you want 2 leave? I'm kinda screwed it means the diff between an A and B for this semester and I got a 75 on my first of 2 attempts

- anonymous

@alexrobin13

- alexrobin13

hey

- anonymous

aight

- anonymous

let me get the next prob

- alexrobin13

aight

- anonymous

https://gyazo.com/a04a14fc23143ca6e1b06d066a2a1e6f

- anonymous

D right?

- alexrobin13

x= (-7)(-6)=42, 4(8)=32, 42+32=74, so C I believe

- anonymous

ohhh got it

- anonymous

Now the 75% is starting to make sense haha

- alexrobin13

Hahah keep working you'll get it

- anonymous

https://gyazo.com/2b9d34424aeccdf0203c299f4502bd97

- anonymous

so you check the magnitude and angle right?

- anonymous

When I did 12 - 7 and 6 - 1 which are both 5 and compared them to the other vector which is 6 - 0 and 5 - 0 which is 6 and 5 I decided that they weren't equal. Is that true?

- alexrobin13

Let me do some quick math, not used to the formatting of the questions.

- alexrobin13

I believe you are right, that's what I found as well

- anonymous

https://gyazo.com/4020eee33b7cf9ffa0602b44e6905953 Pretty sure I got this right since it's the vector over the magnitude

- alexrobin13

Your reasoning makes sense

- anonymous

and same thing for this? https://gyazo.com/eceaa490fd76de53866d70aa88bcd0f9

- alexrobin13

yes!

- anonymous

And how do these work https://gyazo.com/9984897e35d9dd26aeacae012d6e17f3

- anonymous

I know the magnitude but I don't know the second part

- alexrobin13

do you know cos, sin, etc?

- anonymous

yea, I think I'm remembering something. Inverse of tan|(b/a)| right?

- alexrobin13

thats right

- alexrobin13

http://web2.0calc.com/

- anonymous

52.4

- alexrobin13

Correct

- anonymous

So my friend said to do for this https://gyazo.com/8db809d93a89ba4b05105d31dfed12b5 is that right?

- anonymous

Multiplied by 16

- alexrobin13

what are we looking for?

- anonymous

the vector given angle and magnitude

- anonymous

went with D

- alexrobin13

He's right then

- alexrobin13

I found the same

- anonymous

https://gyazo.com/68c1d96365385df186a8a729f241b849 So in this problem a stands for the number in ai + bj linear form thing. So do I do cos45?

- anonymous

which would be rad2/2

- anonymous

but how do I get b?

- alexrobin13

cos for i and sin for j

- anonymous

but do I do sin45?

- alexrobin13

yes, it's the same value as cos45

- anonymous

And why do I use 45 for b when it's a

- alexrobin13

I don't understand your question

- alexrobin13

Oh okay

- anonymous

So it states that a = 45deg. So that's cos45. But how do I know that b is 45deg and do sin45

- alexrobin13

If its the same force/line it will have the same angle

- anonymous

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

- alexrobin13

yes

- anonymous

Ok I have a really crucial question. https://gyazo.com/d69a4eabe6f482f3055e62a211fc559c Last time I did this I got 16sqin no matter how I tried it but it isn't one of the answer choices. Is the problem wrong?

- alexrobin13

whats the question haha

- anonymous

https://gyazo.com/d69a4eabe6f482f3055e62a211fc559c

- alexrobin13

I know but whats it asking

- anonymous

oh mb

- anonymous

Its looking for area using heron's formula

- alexrobin13

I'm not familiar with Heron;s formula, give me a minute.

- alexrobin13

I'm getting 16... as well. Not sure if it's because I'm unfamiliar though

- anonymous

My friend didn't mention any problems with the quiz but this is really frustrating ;p

- anonymous

Do you think it would be safe to guess 32 since it's the only number to have a relationship with 16?

- alexrobin13

Are you sure it's asking that?

- alexrobin13

I don't think it's safe to assume that no

- anonymous

https://gyazo.com/23032fd1f27a5799f10b7217c138df9b

- alexrobin13

I'm really not sure, I really think the answer is 16. Did he have a different test perhaps?

- anonymous

No it's the same. I'm not sure if he got 100% on it though we only talked briefly.

- anonymous

Im going to skip that for now. 2 left. https://gyazo.com/2a5ef5e761a6f80b0f51da44d9bdc478

- alexrobin13

I even put the info in a calculator, giving me 16.

- anonymous

I think my teacher put in the wrong answers

- alexrobin13

Maybe, what'd you get for the next one

- anonymous

so for https://gyazo.com/2a5ef5e761a6f80b0f51da44d9bdc478 I would start with the x1 vector spot and do -8 = x - (-2)

- alexrobin13

I think A

- anonymous

I mean -8 = -2 - x

- alexrobin13

which gives you 6

- anonymous

yea which then repeated for the x2 spot gives me 3

- anonymous

cool

- alexrobin13

awesome

- anonymous

https://gyazo.com/52335054c6eb4ff90e30592ca0a689b2

- alexrobin13

B?

- alexrobin13

Do you agree

- anonymous

so I found the magnitude which was 5^2 + 12^2 which was 169 who's sqrt is 13 so B?

- alexrobin13

yes

- anonymous

So I have 5 problems left but they're simply solving triangles using either heron's or law of sines or law of cosine. The only troublesome one is that silly incorrect one

- alexrobin13

Okay!

- anonymous

So what do you think I should do about it?

- alexrobin13

Answer 12, it's the closest to 16, and politely ask your teacher to explain to you how to find the right answer. They'll probably find their mistake.

- anonymous

ok

- alexrobin13

ok

- anonymous

Do you think I can use a online triangle solver to check myself for those other 5?

- alexrobin13

Definitely, just be careful entering values!

- alexrobin13

if you have any trouble let me know

- anonymous

Ok I'll fan+medal

- alexrobin13

awesome

- anonymous

Do you think that it's possible that he did the problem in radians and not degrees?

- anonymous

90%

Looking for something else?

Not the answer you are looking for? Search for more explanations.