anonymous
  • anonymous
If csc alpha = 7/3 and cot alpha= 2 square root of 10 over 3 find sec alpha
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
think of cosecant as "hypotenuse over adjacent" and draw a triangle
misty1212
  • misty1212
find the missing side via pythagoras then you can take any trig ratio you like

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anonymous
  • anonymous
After I find the missing side do I multiply them and use the keep change flip method?
misty1212
  • misty1212
not sure what you are asking
misty1212
  • misty1212
other side is \[\sqrt{7^2-3^2}=\sqrt{49-9}=\sqrt{40}=2\sqrt{10}\]
anonymous
  • anonymous
For the missing side it was square root of 40
misty1212
  • misty1212
yeah \(\sqrt{40}\) or \(2\sqrt{10}\)
misty1212
  • misty1212
oh wow i made a huge mistake
anonymous
  • anonymous
What happens after that how do I find sin if both cot and csc is 2 square root of 10
misty1212
  • misty1212
cosecant is the reciprocal of sine not cosine
anonymous
  • anonymous
Yea
misty1212
  • misty1212
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misty1212
  • misty1212
secant is the reciprocal of cosine, so it is hypotenuse over adjacent i.e. \[\frac{7}{2\sqrt{10}}\]
anonymous
  • anonymous
So we multiply square root of ten on both top and bottom to cancel the square root and it gives me the final answer of 7 square root 10 over 20 thank u so much!!!!

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